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kati45 [8]
3 years ago
14

The scale of a map is 5 mm = 2 feet. What is the map distance if the actual distance is 50 feet. BE SURE TO LABEL!

Mathematics
2 answers:
Vikentia [17]3 years ago
7 0
It would probably be 20 feet if I’m not wrong
Murljashka [212]3 years ago
5 0
It should be 20 feet!!!!!!!!!!!
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Assume the parent function has been shifted up
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Answer:

If y=(x-2)^2+4 is the transformed function, then the parent function y=x^2 has been shifted up vertically by 4 units and horizontally right by 2 units

Step-by-step explanation:

Assume the function is y=f(x) is the parent function.

A vertical shift,b units up  will transform the function to y=f(x)+b .

A horizontal shift a units.

y=f(x-a)+b

For instance, if y=x^2, b=4, and a=2 units.  

Then the transformed function becomes:

y=(x-2)^2+4

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Express the function as the sum of a power series by first using partial fractions. f(x) = 8 x2 − 4x − 12 f(x) = ∞ n = 0 find th
alexandr1967 [171]

I'm guessing the function is

f(x)=\dfrac8{x^2-4x-12}=\dfrac8{(x-6)(x+2)}

which, split into partial fractions, is equivalent to

\dfrac1{x-6}-\dfrac1{x+2}

Recall that for |x| we have

\dfrac1{1-x}=\displaystyle\sum_{n=0}^\infty x^n

With some rearranging, we find

\dfrac1{x-6}=-\dfrac16\dfrac1{1-\frac x6}=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n

valid for \left|\dfrac x6\right|, or |x|, and

\dfrac1{x+2}=\dfrac12\dfrac1{1-\left(-\frac x2\right)}=\displaystyle\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n

valid for \left|-\dfrac x2\right|, or |x|.

So we have

f(x)=\displaystyle-\frac16\sum_{n=0}^\infty\left(\frac x6\right)^n-\frac12\sum_{n=0}^\infty\left(-\frac x2\right)^n

f(x)=\displaystyle-\sum_{n=0}^\infty\left(\frac{x^n}{6^{n+1}}+\frac{(-x)^n}{2^{n+1}}\right)

f(x)=\displaystyle-\sum_{n=0}^\infty\frac{1+3(-3)^n}{6^{n+1}}x^n

Taken together, the power series for f(x) can only converge for |x|, or -2.

6 0
3 years ago
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