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larisa [96]
3 years ago
11

One fourth of the quantity three squared

Mathematics
1 answer:
pashok25 [27]3 years ago
6 0
NMakamskmslskMmalakMkskskskskksksksksksskkskskskskskskskskskskss
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Write a trinomial with 3x as the GCF of its terms.​
Sonja [21]

Answer:

3x (x² + x + 1)

You could write any trinomial like this

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I need help! I'm stuck on answering these problems!!<br>​
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What is the product of 3800 and 9.9 * 10^5 expressed in scientific notation?
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Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the

10

. The sign of the exponent will depend on the direction you are moving the decimal.

3.762

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Which data will most likely have variability for a school during a single school year?
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A

Step-by-step explanation:

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An automobile manufacturer claims that its car has a 33.7 miles/gallon (MPG) rating. An independent testing firm has been contra
Gnoma [55]

Answer:

z=\frac{34-33.7}{\frac{1.6}{\sqrt{120}}}=2.05  

And the p value would be given by:

p_v= 2*P(z>2.05) = 0.0404

And since the p value is higher than the significance level we have enough evidence to fail to reject the null hypothesis.

Step-by-step explanation:

Data given and notation  

\bar X=34 represent the sample mean

\sigma=\sqrt{2.56}= 1.6 represent the population standard deviation

n=120 sample size  

\mu_o =33.7 represent the value that we want to test  

\alpha=0.02 represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

System of hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is 33.7 mpg or no, the system of hypothesis would be:  

Null hypothesis:\mu =33.7  

Alternative hypothesis:\mu \neq 33.7  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{34-33.7}{\frac{1.6}{\sqrt{120}}}=2.05  

And the p value would be given by:

p_v= 2*P(z>2.05) = 0.0404

And since the p value is higher than the significance level we have enough evidence to fail to reject the null hypothesis.

6 0
3 years ago
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