![14\sqrt[]{6}i](https://tex.z-dn.net/?f=14%5Csqrt%5B%5D%7B6%7Di)
1) Let's rewrite it into the z=a +bi form.
2) So we can write out the following noticing that i² =-1 as well as √-1=i
![\begin{gathered} \sqrt[]{-1176}=\sqrt[]{-1}\cdot\sqrt[]{1176} \\ Factoring \\ \sqrt[]{-1}\cdot14\sqrt[]{6} \\ i\cdot14\sqrt[]{6} \\ 14\sqrt[]{6}i \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csqrt%5B%5D%7B-1176%7D%3D%5Csqrt%5B%5D%7B-1%7D%5Ccdot%5Csqrt%5B%5D%7B1176%7D%20%5C%5C%20Factoring%20%5C%5C%20%5Csqrt%5B%5D%7B-1%7D%5Ccdot14%5Csqrt%5B%5D%7B6%7D%20%5C%5C%20i%5Ccdot14%5Csqrt%5B%5D%7B6%7D%20%5C%5C%2014%5Csqrt%5B%5D%7B6%7Di%20%5Cend%7Bgathered%7D)
Note that in this number the real part "a" is equal to 0.
Answer:
II
Step-by-step explanation:
The first quadrant is in the top left so the second is top right.
Answer:
Man i also need this please everyone who knows answer thisssss
Step-by-step explanation:
PLEASE!
Answer:
Endless
Step-by-step explanation:
There are endless possibilities for x, because 1 to the power of any x will always be 1.