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2 years ago

Find the area of the given trapezoid: A = ...... square units

Mathematics

1 answer:

RideAnS [48]2 years ago

5 0

Answer:

A = 48 square units

Step-by-step explanation:

The dimensions between two markings on the coordinate plane = 2 unit

The trapezoid is located sideways

The area of a trapezoid, A = ((a + b)/2) × h

Where;

a = The long base side

b = The short base side

h = The height

The long base side length AT = 4 space between markings = 4 × 2 units = 8 units

The short base side length SR = 2 space between markings = 2 × 2 units = 4 units

The height, h = 4 space between markings = 4 × 2 units = 8 units

The area of the trapezoid, A = ((4 unit + 8 unit)/2) × 8 unit = 48 square units.

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3 years ago

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3 years ago

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3 years ago

What is the period, in seconds, of a simple pendulum of length 2 meters? Use the gravitational constant g = 9.8 m/s^2 and round

kirill [66]

Answer:

The period, in seconds to two decimal places is, 2.84 sec

Step-by-step explanation:

Using formula:

$T = 2 \pi \sqrt{\frac{l}{g}}$ ......[1]

where

T represents the Time period in second

l represents the length of the pendulum/

As per the statement:

Use the gravitational constant g = 9.8 m/s^2 , length of the simple pendulum(l) = 2 meters and $\pi = 3.14$

Substitute the given values we have;

$T = 2\cdot 3.14 \cdot \sqrt{\frac{2}{9.8}}$

⇒ $T = 6.28 \cdot \sqrt{\frac{1}{4.9}}=6.28 \cdot \frac{1}{2.21359436212}= \frac{6.28}{2.21359436212} = 2.83701481512$

Therefore, the period, in seconds to two decimal places is, 2.84 sec

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3 years ago