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3 years ago

Can you help with this math please?

Mathematics

1 answer:

Blababa [14]3 years ago

3 0

Answer:

3 on the other side and 7 and 7 on the sides

Step-by-step explanation:

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When 300 college students were surveyed, 220 said they own their car. Find a point estimate for p, the population proportion of

Scilla [17]

$\text{Hello there!}\\\\\text{Point estimates would be represented as:}\,\,p=\frac{x}{t}\\\\\text{"x" would represent the value you know}\\\\\text{"t" would represent your total}\\\\\text{To find your point value, you would divide 220 by 300}\\\\220\div300=0.73333333\\\\\text{Round to the nearest thousandths place}\\\\\boxed{0.733}$

4 0

3 years ago

The graph shows how many calories are in different amounts of popcorn. Which of these statements is true?

wlad13 [49]

Answer:

50 calories per cup of popcorn

Step-by-step explanation:

just subtract 25

5 0

3 years ago

Read 2 more answers

Please solve the equation (15m + 3)/2 = -6

stiv31 [10]

Answer:

m = - 1

Step-by-step explanation:

Given

$\frac{15m+3}{2}$ = - 6

Multiply both sides by 2 to clear the fraction

15m + 3 = - 12 ( subtract 3 from both sides )

15m = - 15 ( divide both sides by 15 )

m = - 1

6 0

3 years ago

Read 2 more answers

Two consecutive integers have sum of 137

Mazyrski [523]

You would do x+ (x+1)=137
2x+1=137
Subtract 1 from each side
2x=136
x=68.
Add 1 to 68, since they are consecutive integers.
The answer is 68 and 69

5 0

3 years ago

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The 13th term of a geometric sequence is 16, 384 and the first term is 4. What is the common ratio?

AleksAgata [21]

Answer:

$\large \boxed{2}$

Step-by-step explanation:

The formula for the nth term of a geometric sequence is

aₙ = a₁rⁿ⁻¹

In your geometric sequence, a₁ = 4 and a₁₃ = 16 384.

$\begin{array}{rcl}16384 & = & 4r^{(13 - 1)}}\\16384 & = & 4r^{12}\\4096 & = & r^{12}\\3.6124 & = & 12 \log r\\0.30102 & = & \log r\\r & = & 10^{0.30102}\\ & = & \mathbf{2}\\\end{array}\\\text{The common ratio is $\large \boxed{\mathbf{2}}$}$

Check:

$\begin{array}{rcl}16384 & = & 4(2)^{12}\\16384 & = & 4(4096)\\16384 & = & 16384\\\end{array}$

It checks.

7 0

3 years ago