They all add 3 then subtract it by 4
First, you have to find the median, which is the number in the middle: 25
Then cut the data in half by the median, so your new data sets are
15,29,20
and
31,38,41
Now you find the median of both of those sets, which is 29 and 38.
The interquartile range is the difference between the numbers, so 38-29 = 9.
I belive this is -3x+3/x^3
hope this helps!
Answer:
Yes, the event are mutually exclusive...
Step-by-step explanation:
Event are mutually exclusive if those event cannot occur at the same time. That is the definition of mutually exclusive for instance in a football match, a certain team canot score 0 and 2goals in a match, it is either he scored 2goals or zero goals... In a throw of a coin we cannot have head and tail at the same time, it is either we have a head or a tail, all the event are mutually exclusive.
Now if we have a dealer selling blue car and two doors car. Let say 20% are blue and 10% have two doors. Then, this are not mutually exclusive because we can have a car that is blue and have two doors.
Mutually exclusive events are like disjoint set in SET theory, where A intersection B intersection C is equal to empty set.
Where A n B n C= {} empty set
Answer: 53.13
Explanation of answer: since theta is the unknown, then you must use the inverse of sin. (Which is sin with -1 subscript) I used a calculator and used inverse of sin and put 4/5 in parenthesis
