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Semenov [28]
3 years ago
14

Suppose y varies inversely with x. Write an equation if y=7 when x=-4

Mathematics
1 answer:
luda_lava [24]3 years ago
3 0

Answer:

y = -28 ÷ x

Step-by-step explanation:

The standard format of a inversely proportional equation goes by the format of y = k ÷ x. The question asks us to write an equation if y = 7 when x = -4 and y varies inversely with x.

So we substitute the values y = 7 and x = -4 in the equation y = k ÷ x

K = constant, we have to work this out

7 = k ÷ -4

7 × - 4 = k

k = - 4 × 7

k = -28

k = -28 So then we put this back into the original y = k ÷ x to find our final equation which is y = -28 ÷ x

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The weights (in pounds) of 18 preschool children are
ivanzaharov [21]

Answer:

22.8 and 37.5

Step-by-step explanation:

Given the

The weights (in pounds) of 18 preschool children are

32, 20, 25, 27, 31, 22, 30, 23, 44, 37, 33, 45, 41, 24, 34, 21, 39, 29

To find its 20th percentile and 75th percentile.

In ascending order we get like this

Position  X (Asc. Order)

1  20

2  21

3  22

4  23

5  24

6  25

7  27

8  29

9  30

10  31

11  32

12  33

13  34

14  37

15  39

16  41

17  44

18  45

Percentile position = (no of entries +1)20/100 = 19/5 = 3.8

Since posiiton is not integer we use interpolation method.

The value of 3.8 - 3 = 0.8 corresponds to the proportion of the distance between 22 and 23 where the percentile we are looking for is located at.

Hence 20th percentile = 22+0.8(23-22)=22.8

So answer is 22.8

----------------------

75th percentile

Percentile posiiton = 19(75)/100 = 14.25

75th percentile= 37+0.25(39-37)=37.5

6 0
3 years ago
C=5x-3(4x-2(4x-3(5x-20))
stiv31 [10]
The answer would be C = -73x + 360.
5 0
3 years ago
Height of a wedding cake as 5 inch layers are added
prisoha [69]
? what is the question
8 0
3 years ago
Solve equation 14d-5=8a+31
sdas [7]
It is easy to go to tiger math and type that in
4 0
3 years ago
Read 2 more answers
-5x+7y=11<br> -5x+3y=19<br> Elimination
lesantik [10]

\left\{\begin{array}{ccc}-5x+7y=11&\text{change the signs}\\-5x+3y=19\end{array}\right\\\underline{+\left\{\begin{array}{ccc}5x-7y=-11\\-5x+3y=19\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad\qquad-4y=8\qquad\text{divide both sides by (-4)}\\.\qquad\qquad \boxed{y=-2}\\\\\text{Upt the value of y to the second equation:}\\\\-5x+3(-2)=19\\-5x-6=19\qquad\text{add 6 to both sides}\\-5x=25\qquad\text{divide both sides by (-5)}\\\boxed{x=-5}\\\\Answer:\ \boxed{x=-5\ and\ y=-2\to(-5,\ -2)}

6 0
3 years ago
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