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2 years ago

State the question which is definitely come in tomorrow 10th board exam

Mathematics

1 answer:

Bas_tet [7]2 years ago

6 0

Proof of from an external point tangents are equal in a circle

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If pqr= 1 show that 1/(1+p+q^-1)+1/(1+q+r^-1)+1/(1+r+p^-1) = 1.<br>

mariarad [96]

Answer:

Step-by-step explanation:

1/(1+p+q^-1)+1/(1+q+r^-1)+1/(1+r+p^-1) = 1.

7 0

2 years ago

Read 2 more answers

Find the gcf of each pair of monomials <br> 6x2 and 5x2

aleksandrvk [35]

Answer:

its 2

Step-by-step explanation:

so 6x2 is 12 and 5x2 is 10

u have to find the gcf of 12 and 10 which is 2 :)

8 0

2 years ago

Tyra has 12 2/3 cups of sugar. If r is the amount of sugar called for in one batch of cookies, the expression 12 2/3 ÷ r can be

faust18 [17]

Answer:

13 batches of cookies

Step-by-step explanation:

12 2/3 ÷ 2/3 = 12.6666667, it's 13 because 2/3 as a decimal is .6666666 and .6666667 is more than 2/3. So you add one to the answer.

4 0

2 years ago

Read 2 more answers

A tank contains 1600 L of pure water. Solution that contains 0.04 kg of sugar per liter enters the tank at the rate 2 L/min, and

goldfiish [28.3K]

Let S(t) denote the amount of sugar in the tank at time t. Sugar flows in at a rate of

(0.04 kg/L) * (2 L/min) = 0.08 kg/min = 8/100 kg/min

and flows out at a rate of

(S(t)/1600 kg/L) * (2 L/min) = S(t)/800 kg/min

Then the net flow rate is governed by the differential equation

$\dfrac{\mathrm dS(t)}{\mathrm dt}=\dfrac8{100}-\dfrac{S(t)}{800}$

Solve for S(t):

$\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{S(t)}{800}=\dfrac8{100}$

$e^{t/800}\dfrac{\mathrm dS(t)}{\mathrm dt}+\dfrac{e^{t/800}}{800}S(t)=\dfrac8{100}e^{t/800}$

The left side is the derivative of a product:

$\dfrac{\mathrm d}{\mathrm dt}\left[e^{t/800}S(t)\right]=\dfrac8{100}e^{t/800}$

Integrate both sides:

$e^{t/800}S(t)=\displaystyle\frac8{100}\int e^{t/800}\,\mathrm dt$

$e^{t/800}S(t)=64e^{t/800}+C$

$S(t)=64+Ce^{-t/800}$

There's no sugar in the water at the start, so (a) S(0) = 0, which gives

$0=64+C\impleis C=-64$

and so (b) the amount of sugar in the tank at time t is

$S(t)=64\left(1-e^{-t/800}\right)$

As $t\to\infty$ , the exponential term vanishes and (c) the tank will eventually contain 64 kg of sugar.

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3 years ago

At 10:00 AM Han and Tyler

NARA [144]

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2 years ago