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3 years ago

A contractor is buying doors for a new office building. If two doors are

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

6 0

Answer:

562 $ for nine doors

Step-by-step explanation:

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1. Simplify: a^7/a^4

IgorC [24]

1)a^7/a^4
=a^[7-4]
=a³

2) r²s⁴t/r²st³
=s⁴-¹.t¹-³
=s³.t-²
=s³/t²

3)3x^6/18x
=x^5/6

6 0

3 years ago

Members of the swim team want to wash their hair. The bathroom has less than 5600 liters of water and at most 2.5 liters of sham

nordsb [41]

Answer:

Yes, the bathroom has enough water and shampoo for all of them.

Step-by-step explanation:

70L+ 60S < 5600

Putting 8 into L and 7 into S, gives:

70(8) + 60(7) = 560 + 420 = 980

That is definitely less than 5600, so water is OK.

Now,

0.02L + 0.01S

Putting 8 into L and 7 into S, gives:

0.02(8) + 0.01(7) = 0.16 + 0.07 = 0.23

That's definitely less than 2.5 liters, so shampoo is OK as well.

Hence, bathroom has enough water and shampoo for them.

7 0

3 years ago

Read 2 more answers

4. Determine all unknown sides and angles to 1 decimal place.

Ksju [112]

Answer:

The unknown sides are 60.81cm and 51.57cm while the unknown angle is 58degrees

Step-by-step explanation:

4a) Given the following

Opposite side = 38cm (side facing the given angle)

Required

Adjacent and hypotenuse side

According to SOH CAH TOA

$tan \theta = \frac{opp}{hyp}\\tan 32=\frac{38}{hyp}\\hyp=\frac{38}{tan 32}\\hyp=\frac{38}{0.6249}\\hyp= 60.81cm$

Next is to get the adjacent

$Cos 32=\frac{adj}{60.81}\\adj=60.81cos32\\adj=60.81(0.8480)\\adj= 51.57cm$

Next is to get the missing

Since sum of angle in the triangle is 180degrees

32 + 90 + x = 180

122 + x = 180

x = 180 - 122

x = 58degrees

7 0

3 years ago

A mountain has a 20 degree slope, and is 1 mile tall. How far do you need to hike to reach the summit?

netineya [11]

Answer:21

Step-by-step explanation:

3 0

3 years ago

1. Simplify. 5–1(3–2)

konstantin123 [22]

Answer with explanation:

Using following law of indices

$1.x^a \times x^b=x^{a+b}\\\\2. (x^m)^n=x^{mn}\\\\ 3. x^{-n}=\frac{1}{x^n}\\\\4. \frac{x^m}{x^n}=x^{m-n}$

$1.5^{-1}\times 3^{-2}=\frac{1}{5}\times\frac{1}{3^2}\\\\=\frac{1}{5\times9}\\\\=\frac{1}{45}\\\\2. \frac{mn^{-4}}{p^0*q^{-2}}=\frac{mq^2}{n^4}\\\\ 3.0.0042=4.2\times 10^3\\\\4.6.12 \times 10^3=6.12 \times 1000=6120\\\\ 5.0.5 \times(8\times10^5})=\frac{1}{2}\times8 \times 10^5=4\times 10^5\\\\6. (9 \times 10^3)^2=9^2 \times (10^3)^2=81 \times 10^6\\\\7.( \frac{1}{2}a^{-4}\times b^2 )_{a=-2,b=4}{\text{or}}( \frac{1}{2}a^{4}\times b^{-2} )_{a=-2,b=4}=\frac{1}{2}\times (-2)^{-4}\times(4)^2{\text{or}}=\frac{1}{2}\times (-2)^{4}\times(4)^{-2}=\frac{16}{2\times16}=\frac{1}{2}$

$9. (4\times x\times y^2)^3\times (xy)^5=4^3\times x^3\times (y^2)^3\times x^5 \times y^5\\\\=64\times x^{3+5}\times y^{5+6}\\\\=64x^8y^{11}\\\\10.(2\times t^3)^3(0.4\times r)^2=2^3 \times (t^3)^3\times (0.4)^2 \times r^2=8\times t^9 \times 0.16 \times r^2=1.28r^2t^9$