The technique of matrix isolation involves condensing the substance to be studied with a large excess of inert gas (usually argon or nitrogen) at low temperature to form a rigid solid (the matrix). The early development of matrix isolation spectroscopy was directed primarily to the study of unstable molecules and free radicals. The ability to stabilise reactive species by trapping them in a rigid cage, thus inhibiting intermolecular interaction, is an important feature of matrix isolation. The low temperatures (typically 4-20K) also prevent the occurrence of any process with an activation energy of more than a few kJ mol-1. Apart from the stabilisation of reactive species, matrix isolation affords a number of advantages over more conventional spectroscopic techniques. The isolation of monomelic solute molecules in an inert environment reduces intermolecular interactions, resulting in a sharpening of the solute absorption compared with other condensed phases. The effect is, of course, particularly dramatic for substances that engage in hydrogen bonding. Although the technique was developed to inhibit intermolecular interactions, it has also proved of great value in studying these interactions in molecular complexes formed in matrices at higher concentrations than those required for true isolation.
Answer:
155.25= 12
Step-by-step explanation:
17/2*2*1/2 = 12
17*1/2 = 12
8 1/2 17/1* 1/2
8*2+1 17*1/1*2
2 17*1/1*2
16+1 17/1*2
2 17/2
17 8.5=12
2
Answer:
12 dollars 80% divided by 15 dollars
Step-by-step explanation:
a.
Let
5x = number of games won
2x = number of games lost
The total number of win and lose is 154. So
5x + 2x = 154
Solving for x,
7x = 154
x = 22
Therefore, the number of games won is 5*22=110 and the number of games lost is 2*22 is 44.
b.
Let
6x = first side of the triangle
7x = second side of the triangle
9x = third side of the triangle
The perimeter of a triangle is the total of all sides. So,
6x + 7x + 9x = 88
22x = 88
x = 4
Therefore, the three lengths of the side are 6*4=24, 7*4=28, and 9*4 = 36
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<h2>
Answer and Explanation to questions 13,14,15</h2>
13) 
as given in the question.
14) 
Since Y is the midpoint of XZ. So, Y will divide XZ in equal halves into XY and YZ.
15) 
and 
. So, 
<h2>
Answer and Explanation to questions 16,17,18</h2>
∠3 is supplementary to ∠1 means: ∠3 + ∠1 = 180°
And, according to figure ∠1 + ∠2 = 180° as ∠1 and ∠2 form a straight line.
∠3 + ∠1 = 180° .............(i)
∠1 + ∠2 = 180° .............(ii)
subtracting equation (i) and (ii) will give ∠3 = ∠2 ..........(iii)
15) ∠3 is supplementary to ∠1 as given in the question
16) ∠2 is supplementary to ∠1 as shown be equation (ii)
18) ∠3 ≅ ∠2 as shown by equation (iii)
<h2>
Answer and Explanation to questions 19</h2>
∠3 and ∠4 form a straight line. Therefore, ∠3 + ∠4 = 180° .......(i)
∠4 and ∠5 form a straight line. Therefore, ∠4 + ∠5 = 180° .......(ii)
subtracting equation (i) and (ii)
∠3 + ∠4 - (∠4 + ∠5) = 180°-(180°)
∠3 + ∠4 - ∠4 - ∠5 = 180°-180°
∠3 - ∠5 = 0
∴ ∠3 = ∠5 (Hence Proved)
