All categories

3 years ago

I need help for grades!!!

Mathematics

1 answer:

irina1246 [14]3 years ago

5 0

Yes, the relation shown is a function because every element in the domain has only one distinct image in the co-domain.

You might be interested in

In Bonaparte Valley School District, 13% of all students play football and baseball and 25% of all students play baseball. What

vladimir1956 [14]

Answer:

13/25 or 52%

Step-by-step explanation:

7 0

3 years ago

Find the value of c that completes the square

Kitty [74]

Answer:

c = 64

Step-by-step explanation:

Given

x² - 16x + c

To complete the square

add ( half the coefficient of the x- term )² to x² - 16x

x² + 2(- 8)x + 64

= (x - 8)²

Thus

x² - 16x + 64 = (x - 8)² ← a perfect square

with c = 64

8 0

2 years ago

1/3 is greater than what other fractions

Novosadov [1.4K]

As 1/3 = 2/6 = 3/9 = 4/12

and 2/6 is greater than 1/6
3/9 is greater than 2/9
etc..

So

1/3 is greater than 1/6 ; 2/9 ; ...

7 0

3 years ago

Read 2 more answers

The questionnnnnnnnn

CaHeK987 [17]

I’m pretty sure the answer is C

3 0

2 years ago

Read 2 more answers

The general form of an parabola is 2x2−12x−3y+12=0 .

Murljashka [212]

Answer:

The standard form of the parabola is $(x-3)^2=4*\frac{3}{8}(y+2)$

Step-by-step explanation:

The standard form of a parabola is

$(x-h)^2=4p(y-k)$ .

In order to convert $2x^2-12x-3y+12=0$ into the standard form, we first separate the variables:

$2x^2-12x+3y+12=0\\\\2x^2-12x+12=3y$

we now divided both sides by 2 to remove the coefficient from $2x^2$ and get:

$x^2-6x+6=\frac{3}{2}y$ .

We complete the square on the left side by adding 3 to both sides:

$x^2-6x+6+3=\frac{3}{2}y+3$

$x^2-6x+9=\frac{3}{2}y+3$

$(x-3)^2=\frac{3}{2}y+3$

now we bring the right side into the form $4p(y-k)$ by first multiplying the equation by $\frac{2}{3}$ :

$\frac{2}{3} *(x-3)^2=\frac{2}{3} *(\frac{3}{2}y+3)\\\\\frac{2}{3} *(x-3)^2=y+2$

and then we multiplying both sides by $\frac{3}{2}$ to get

$(x-3)^2=\frac{3}{2} (y+2)$ .

Here we see that

$4p=\frac{3}{2}$

$\therefore p=\frac{3}{8}$

Thus, finally we have the equation of the parabola in the standard form:

$\boxed{(x-3)^2=4*\frac{3}{8}(y+2)}$

5 0

3 years ago