one number is 8 times a first number. a third number is 100 more than the first number. if the sum of the three numbers is 480,
find the numbers
1 answer:
Answer:
Step-by-step explanation:
Let the first number = x
Let the second number = 8x
Let the third number = x + 100
x + 8x + x + 100 = 480 Combine like terms
10x + 100 = 480 Subtract 100
<u> - 100 -100</u>
10x = 380 Divide by 10
x = 380/10
x = 38
First number = 38
Second number = 8*38 = 304
The third number = 38 + 100 = 138
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