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Iteru [2.4K]
3 years ago
11

Please help me with this question:)

Mathematics
1 answer:
Alex73 [517]3 years ago
3 0

Answer:

Range = {0,15}

Step-by-step explanation:

Domain is the set of x values for which the function is defined and the range is the set of y values corresponding to the domain.

We need to find the range of the function, given domain.

The domain is given as 3 numbers : {-3,0,5}

We have to plug in these 3 numbers individually in "x" of the function to find corresponding y values (range).

First, -3,

y = (-3)^2 -2(-3) = 15

Next, 0,

y = 0^2 - 2(0) = 0

Last, 5,

y = (5)^2 -2(5) = 15

So the range is {15,0,15}. We don't have to put the same number twice (15), so we write the range as:

Range = {0,15}

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Dafna1 [17]

Answer: 80000

Step-by-step explanation:

p=<u>f </u>

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<u>24</u>

0.003

NOTE:30  ÷10000=<u>0.030km</u>

7 0
3 years ago
Can someone help me with this question ​
OLga [1]

Answer:

I believe it is because it does not start at 0

3 0
3 years ago
The product of (3 − 4i) and____is 25.
LiRa [457]

(3-4i)(a+bi)=25\qquad\text{use FOIL method}\\\\(3)(a)+(3bi)+(-4i)(a)+(-4i)(bi)=25+0i\\\\3a+3bi-4ai-4bi^2=25+0i\\\\3a+3bi-4ai-4b(-1)=25+0i\\\\3a+3bi-4ai+4b=25+0i\\\\(3a+4b)+(3b-4a)i=25+0i\\.\qquad\qquad\qquad\qquad\Downarrow\\\\3a+4b=25\ and\ 3b-4a=0\\\\3b-4a=0\qquad\text{add 4a to both sides}\\\\3b=4a\qquad\text{divide both sides by 3}\\\\b=\dfrac{4}{3}a\qquad\text{substitute it to the first equation}\\\\3a+4\left(\dfrac{4}{3}a\right)=25\\\\3a+\dfrac{16}{3}a=25\qquad\text{multiply both sides by 3}

9a+16a=75\\\\25a=75\qquad\text{divide both sides by 25}\\\\\boxed{a=3}\qquad\text{put the value of a to}\ b=\dfrac{4}{3}a:\\\\b=\dfrac{4}{3}(3)\\\\\boxed{b=4}\\\\Answer:\ \boxed{(3-4i)\underline{(3+4i)}=25}

6 0
3 years ago
In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.
Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

5 0
3 years ago
Read 2 more answers
What is nine tenths in standard form?<br> I know it's simple but I forgot.
Fiesta28 [93]
That would be 0.9 because 9 is in the tenths place
5 0
3 years ago
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