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Mila [183]
3 years ago
5

The cost of K-12 education per student was $2200 in 1978 and increased to $10,300 in 2008. (Source: Department of Education). (a

) Find a linear equation that models these data. Let C represent the cost per student and x represent the number of years after 1978.
Mathematics
1 answer:
kobusy [5.1K]3 years ago
6 0

Answer: C=270x+2200

Step-by-step explanation:

Given

Cost per student in the year 1978 is $2200

The cost increases to $10,300 in 2008

Suppose C=mx+a is the linear equation defining the cost per student after x years

Substitute the value for 1978

\Rightarrow 2200=m(0)+c\\\Rightarrow c=2200

After 30 years it becomes

\Rightarrow 10,300=m(30)+2200\\\Rightarrow 30m=8100\\\Rightarrow m=270

Thus, the linear equation becomes

\Rightarrow C=270x+2200

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beks73 [17]

Answer:

In 68229 ways can the quiz be selected such that there is atleast three multiple choice questions

Step-by-step explanation:

Given:

Number of True or false questions= 10

Number of multiple choice questions= 20

To Find:

How many ways can 5 questions can be selected if there must be at least three multiple choice questions =?

Solution:

Combination

A combination is a mathematical technique that determines the number of possible arrangements in a collection of items where the order of the selection does not matter. In combinations, you can select the items in any order.  

The question States there sholud be ATLEAST 3 multiple choice question,

So, we may have

(3 Multiple choice question and 2 true or false question) or

(4 Multiple choice question and 1 true or false question) or

(5 Multiple choice question and 0 true or false question)

Required Number of ways = (20C3 X10C2) +(20C4 X10C1) + (20C5 X10C0)

Required Number of ways =(\frac{20!}{20!(20-3)!}\times\frac{10!}{10!(10-2)!})+(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-1)!}) +(\frac{20!}{20!(20-4)!} \times \frac{10!}{10!(10-0)!})

Required Number of ways = ( 1140 x 42) + (4845 x 10) +(15504 x 1)

Required Number of ways = 47880+48450+15504

Required Number of ways = 68229

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Step-by-step explanation:

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5 0
3 years ago
A shop owner can buy two televisions and three DVD players for $1750 or four televisions and one DVD players for $1250. Find the
Alenkasestr [34]

Answer:

Television = $200 and DVD player = $450

Step-by-step explanation:

→ Make 2 equations

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→ Multiply the bottom equation by 3 to make the same variable of d

2t + 3d = 1750

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→ Minus the two equations to isolate the d variable

-10t = -2000

→ Divide both sides by -10 to find the cost of one television

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→ Substitute t = 200 back into 4t + d = 1250

800 + d = 1250

→ Minus 800 from both sides to isolate d

d = 450

7 0
3 years ago
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Answer:

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Step-by-step explanation:

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jarptica [38.1K]

Answer:

\huge\boxed{1.\ 11h-2}\\\boxed{2.\ 2(3m+4n+2)}

Step-by-step explanation:

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2.\\6m+8n+4=2(3m+4n+2)

6 0
3 years ago
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