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Mila [183]
2 years ago
5

The cost of K-12 education per student was $2200 in 1978 and increased to $10,300 in 2008. (Source: Department of Education). (a

) Find a linear equation that models these data. Let C represent the cost per student and x represent the number of years after 1978.
Mathematics
1 answer:
kobusy [5.1K]2 years ago
6 0

Answer: C=270x+2200

Step-by-step explanation:

Given

Cost per student in the year 1978 is $2200

The cost increases to $10,300 in 2008

Suppose C=mx+a is the linear equation defining the cost per student after x years

Substitute the value for 1978

\Rightarrow 2200=m(0)+c\\\Rightarrow c=2200

After 30 years it becomes

\Rightarrow 10,300=m(30)+2200\\\Rightarrow 30m=8100\\\Rightarrow m=270

Thus, the linear equation becomes

\Rightarrow C=270x+2200

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The inverse of the function f(x)  = 4(x-3)² + 2 is f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

The given function is:

f(x)   =  4(x  - 3)²  +  2

To find the inverse of the function:

Make x as the subject of the formula

4(x-3)^2 = f(x) - 2\\(x-3)^2 = \frac{f(x)-2}{4} \\x - 3 = \sqrt{\frac{f(x)-2}{4} } \\x = \sqrt{\frac{f(x)-2}{4} } + 3

Replace x by f^{-1}(x) and replace f(x) by x

f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

Therefore, the inverse of the function is:

f^{-1}(x) = \sqrt{\frac{x-2}{4} } + 3

Learn more here: brainly.com/question/17285960

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Answer:

RADIUS

==================================

PROBLEM

Mary’s bicycle wheel has a circumference of 226.08 cm². What is its radius?

SOLUTION

We can solve this problem using the circumference formula in which π stands for ( 3.14 ), C stands for circumference itself and r stands for radius.

\bold{Formula \: || \: C = 2πr}Formula∣∣C=2πr

\tt{226.08 = 2(3.14) r}226.08=2(3.14)r

'Now to find the radius,Substitute 226.08 for c which is circumference in the formula.

\begin{gathered} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{C = 2πr} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \tt{226.08 = 2(3.14)\red{r}} \\ \\ \: \: \: \: \: \: \: \: \large \tt{ \frac{226.08}{6.28} = \cancel\frac{6.28 \red{r}}{6.28} } \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \boxed{\tt\green{C = 36}}\end{gathered}

C=2πr

226.08=2(3.14)r

6.28

226.08

=

6.28

6.28r

C=36

To check:

\begin{gathered} \small\begin{array}{|c|}\hline \bold{circumference }\\ \\ \tt{C = 2πr} \\ \tt{C = 2(3.14) (36\:cm) } \\ \tt{C = 2(113.04\:cm) } \\ \underline{\tt \green{C = 226.08\:cm }} \\ \hline \end{array} \end{gathered}

circumference

C=2πr

C=2(3.14)(36cm)

C=2(113.04cm)

C=226.08cm

FINAL ANSWER

If Mary's Bicycle has a circumference of 226.08 cm then the radius is 36.

\boxed{ \tt \red{r = 36}}

r=36

==================================

#CarryOnLearning

7 0
2 years ago
Read 2 more answers
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