Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 152.5
For the alternative hypothesis,
µ ≠ 152.5
This is a two tailed test.
Since no population standard deviation is given, the distribution is a student's t.
Since n = 231
Degrees of freedom, df = n - 1 = 231 - 1 = 230
t = (x - µ)/(s/√n)
Where
x = sample mean = 148.9
µ = population mean = 152.5
s = samples standard deviation = 27.4
t = (148.9 - 152.5)/(27.4/√231) = - 2
We would determine the p value using the t test calculator. It becomes
p = 0.047
Since alpha, 0.05 > thanthere sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals the p value, 0.047, then we would reject the null hypothesis. Therefore, At a 5% level of significance, there is sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals
Answer:
its 30
Step-by-step explanation:
if you see the x is in the middle of the line meaning its 30
Answer:
The sum of ages of all 18 pupils in the class = 81
Step-by-step explanation:
Total number of pupil in the class = 18
Average of years in the class = 
Now, 
⇒Average of sum of ages in the class = 4.05
Let us assume the sum of ages of all students in the class = m
By the formula for AVERAGE:
or, m = 18 x 4.5 = 81
Hence, the sum of ages of all 18 pupils in the class = 81
Answer:
The no. of boys = 20
The no. of girls = 12
Step-by-step explanation:
Ratio of no. of boys to girls = 5 : 3
[5 multiplied with something, and 3 multiplied with something, added together makes 32.Thus, that something = x]
5x + 3x = 32
= 8x = 32
=x = 32÷8 = 4
5x = 5 x 4 = 20
3x = 3 x 4 = 12
