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Mila [183]
3 years ago
5

The cost of K-12 education per student was $2200 in 1978 and increased to $10,300 in 2008. (Source: Department of Education). (a

) Find a linear equation that models these data. Let C represent the cost per student and x represent the number of years after 1978.
Mathematics
1 answer:
kobusy [5.1K]3 years ago
6 0

Answer: C=270x+2200

Step-by-step explanation:

Given

Cost per student in the year 1978 is $2200

The cost increases to $10,300 in 2008

Suppose C=mx+a is the linear equation defining the cost per student after x years

Substitute the value for 1978

\Rightarrow 2200=m(0)+c\\\Rightarrow c=2200

After 30 years it becomes

\Rightarrow 10,300=m(30)+2200\\\Rightarrow 30m=8100\\\Rightarrow m=270

Thus, the linear equation becomes

\Rightarrow C=270x+2200

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Find the equation of the straight line that has slope m = -6 and passes through point (2, -7)
MAXImum [283]

Answer:

y

=

3

2

x

+

1

Explanation:

To find the slope  

(

m

)

of the straight line that passes through two points  

(

x

1

,

y

1

)

and  

(

x

2

,

y

2

)

apply:

(

y

1

−

y

2

)

=

m

(

x

1

−

x

2

)

In this example our two points are  

(

0

,

1

)

and  

(

2

,

4

)

Hence:  

(

1

−

4

)

=

m

(

0

−

2

)

−

3

=

−

2

m

→

m

=

3

2

The equation of a straight line in slope  

(

m

)

and intercept  

(

c

)

form is:

y

=

m

x

+

c

In this example:

y

=

3

2

x

+

c

Since the point  

(

0

,

1

)

is on this line  

→

1

=

0

+

c

Hence,  

c

=

1

∴

y

=

3

2

x

+

1

is our required straight line.

Step-by-step explanation:

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3 years ago
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