let me know if the propositions they gave don't match with mine.
thanks
Answer:
1/3(5.2)h cm³
Step-by-step explanation:
A solid right pyramid has a regular hexagonal base with an area of 5.2 cm2 and a height of h cm. Which expression represents the volume of the pyramid?
One-fifth(5.2)h cm3 StartFraction 1 Over 5 h EndFraction(5.2)h cm3
One-third(5.2)h cm3 StartFraction 1 Over 3 h EndFraction(5.2)h cm3
Volume of the pyramid = 1/3 × area × height
Area = 5.2 cm²
Height = h cm
Volume of the pyramid = 1/3 × 5.2 cm² × h cm
= 1/3(5.2)h cm³
Answer:
11.since diagonal are equal of rectangle
QS=RT
4x+6=6x-4
6+4=6x-4x
2x=10
x=10/2
x=5
now
diagonal :4x+6=4*5+6=<u>26</u>
12.
again
QS=RT
9x+12=11x-10
12+10=11x-9x
2x=22
x=11
now
diagonal=9*11+12=99+12=<u>111</u>
Use desmos the graphing tool to figure it out! Good luck!
Step-by-step explanation:
½ [cos(a − b) − cos(a + b)]
Using sum and difference formulas:
½ [cos a cos b + sin a sin b − (cos a cos b − sin a sin b)]
Distribute the negative:
½ (cos a cos b + sin a sin b − cos a cos b + sin a sin b)
Combine like terms:
½ (2 sin a sin b)
Simplify:
sin a sin b
