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2 years ago

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The area of a right triangle is 54 square centimeters. The lengths of the sides of the triangle are each multiplied by 4. What i

s the area of the new triangle?
A).4cm²
B).216cm²
C).864cm²
D).2916cm²

1 answer:

nasty-shy [4]2 years ago

3 0

Answer:

864

Step-by-step explanation:

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Which sum of difference is equivalent to the following expression? 5-3x/5

Aleks04 [339]

Answer:

1-3x/5

Give me brainiest

Step-by-step explanation:

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2 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

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2 years ago

(5x^2−3x−2)−(−2x^2−x+10)<br> Express the answer in standard form

masha68 [24]

Answer:

7x2−2x−12

Step-by-step explanation:

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oksian1 [2.3K]

To find the distance you would use the distance formula which is:
$d = \sqrt{(x2-x1)^{2}+(y2-y1)^{2}} = \sqrt{(2-(-5))^{2}+(7-5)^{2}}$

This equals:
$d = \sqrt{(7)^{2}+(2)^2} = \sqrt{49+4} = \sqrt{53} = 7.2801$

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3 years ago

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A times a to the 7 power

ivolga24 [154]

Answer:

${a}^{8}$

Step-by-step explanation:

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$( - 5)^{8}$

which is = 390 625

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2 years ago