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Murljashka [212]

3 years ago

8

Simplify [7+2(5 - 9)2]/[(4+1)2 - 3(22)

2 answers:

Neporo4naja [7]3 years ago

8 0

$\bf \cfrac{7+2(5-9)^2}{(4+1)^2-3(2^2)}\implies \cfrac{7+2(\stackrel{\downarrow }{-4})^2}{(\underset{\uparrow }{5})^2-3(\underset{\uparrow }{4})}\implies \cfrac{7+2(\stackrel{\downarrow }{16})}{\underset{\uparrow }{25}-3(4)}\implies \cfrac{7+\stackrel{\downarrow }{32}}{25-\underset{\uparrow }{12}} \\\\\\ \cfrac{39}{13}\implies \cfrac{3}{1}\implies 3$

recall PEMDAS, parentheses or groups first, from innermost to outermost, then exponents and so on.

svet-max [94.6K]3 years ago

4 0

Answer:

9/56 is your answer.

Step-by-step explanation:

[7+2(5 - 9)2]/[(4+1)2 - 3(22)=

[7+2(-4)2]/[(5)2-66]=

[7+2(-8)]/[10-66]=

(7+-16)/(-56)=

-9/-56=

9/56 is your answer.

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The sample space of a random experiment is {a, b, c, d, e} with probabilities 0.1, 0.1, 0.2, 0.4, and 0.2 respectively. Let A de

antoniya [11.8K]

Answer:

a) $P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b) $P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c) $P(A') = 1-P(A) =1-0.4=0.6$

d) $P(A \cup B) =0.4 +0.8-0.2 =1.0$

e) The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

Step-by-step explanation:

We have the following space provided:

$S= [a,b,c,d,e]$

With the following probabilities:

$P(a) =0.1, P(b)=0.1, P(c) =0.2, P(d)=0.4, P(e)=0.2$

And we define the following events:

A= [a,b,c], B=[c,d,e]

For this case we can find the individual probabilities for A and B like this:

$P(A) = 0.1+0.1+0.2 = 0.4$

$P(B) =0.2+0.4+0.2=0.8$

Determine:

a. P(A)

$P(A) =P(a)+P(b) +P(c)= 0.1+0.1+0.2 = 0.4$

b. P(B)

$P(B) =P(c) +P(d)+P(e)=0.2+0.4+0.2=0.8$

c. P(A’)

From definition of complement we have this:

$P(A') = 1-P(A) =1-0.4=0.6$

d. P(AUB)

Using the total law of probability we got:

$P(A \cup B) =P(A) +P(B)-P(A \cap B)$

For this case $P(A \cap B) = P(c) =0.2$ , so if we replace we got:

$P(A \cup B) =0.4 +0.8-0.2 =1.0$

e. P(AnB)

The intersection between the set A and B is the element c so then we have this:

$P(A \cap B) = P(c) =0.2$

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3 years ago