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2 years ago

12

Please help me I’m really confused!!

1 answer:

olchik [2.2K]2 years ago

4 0

Answer:

6÷2=3 means that 6 ones can be broken into 3 groups of 2 ones each.

60÷2=30 means that 60 ones can be broken into 30 groups of 2 ones each.

60÷2=30

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This one is a tough one. If you can explain it to me that’ll me great.

Crazy boy [7]

Answer:

C. 73 if I have read the given angle measurements correctly.

The angle measurements I see are:

$219^\circ$

$(x-50)^\circ$

$(x+45)^\circ$ .

Step-by-step explanation:

Those angles together form a full rotation. A full rotation is equal to 360 degrees.

So we have the following equation to solve:

$219+(x-50)+(x+45)=360$

Combine like terms:

$(x+x)+(219-50+45)=360$

Simplify:

$2x+(219-5)=360$

$2x+214=360$

Divide both sides be 2:

$x+107=180$

Subtract 107 on both sides:

$x=180-107$

$x=73$

5 0

2 years ago

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A T-shirt is on sale for 20 % off. The sale price is $18 ,What was the original price?Explain.

Pavel [41]

The original price was $22.5.
18 divided by 0.8 is 22.5.
If you double check 22.5 times 0.8, you will get 18, your sales price.

6 0

3 years ago

Y=-5/8x+3/2 in standard form

Pani-rosa [81]

Answer:

y=0.625

Step-by-step explanation:

8 0

2 years ago

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A media company wants to track the results of his new marketing plan so the video production manager recorded the number of use

konstantin123 [22]

Answer:

$f(x)=5120(5)^{x}$

Step-by-step explanation:

From the image, f(x) and x are rlated by

$f(x)=a( {b})^{x}$

where b is the common ratio

We first find the value for b

$\frac{6400}{5120}= 5$

$\frac{8000}{6400}= 5$

$\frac{10000}{8000} = 5$

$\frac{12500}{10000} = 5$

$\frac{15625}{12500}=5$

so we can say the common ratio, b=5

we put in any value of f(x) and the corresponding value for x to find a value

Let put x=0 and f(x)=5120

This implies that

$5120 = a(5)^{0}$

but

$5^{0} = 1$

Hence a=5120

Thus the equation which model the relationship between the weeks and the viewers is

$f(x)=5120(5)^{x}$

6 0

2 years ago

Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

6 0

3 years ago

Read 2 more answers