You can first convert the mixed numbers into fractions and then operate them
if for example you have 3 4/3
to convert it you first multiply the whole by the denominator and then you add the nominator. The denominator is the same.
so 3 4/3=13/3
Hello here is a solution :
Answer:
multiply the number with 10 or 15%
Step-by-step explanation:
Answer:
a) Positive linear
b) 72
c) Marks scored when no time is spend on homework.
Step-by-step explanation:
a) relationship between the hours spent on homework and the test scores
As the time spent on homework increases the test score increases.
Similarly if less time is spent on homework, there would be a decrease in test score.
The two variables are directly related.
Thus, there relationship can be expressed as a positive linear relationship.
b) The model function
![y= 8x + 40](https://tex.z-dn.net/?f=y%3D%208x%20%2B%2040)
where y is the test score and x is the time spent on homework in hours.
Score predicted by model when x = 4
![y(4)= 8(4) + 40 = 32 +40 = 72](https://tex.z-dn.net/?f=y%284%29%3D%208%284%29%20%2B%2040%20%3D%2032%20%2B40%20%3D%2072)
Thus, model predict that the score on test will be 72 when 4 hours are spent on homework.
c) Interpretation of 40
When x = 0
![y(0)= 8(0) + 40 = 40](https://tex.z-dn.net/?f=y%280%29%3D%208%280%29%20%2B%2040%20%3D%2040)
Interpretation:
Thus, when Paul spends no time on homework that is zero hours are spend on homework, then, Paul will score 40 on test.
Answer:
56m
Step-by-step explanation:
<h3><u>Diagram</u>:-</h3>
![\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier (0,0)(0,0)(5,0)\qbezier (0,0)(0,0)(0,3)\qbezier (0,3)(0,3)(5,3)\qbezier (5,3)(5,3)(5,0)\qbezier (0,3)(5,0)(5,0)\qbezier (0,0)(0,0)(5,3)\put (-0.4,-0.2){\sf D}\put (-0.2,3.1){\sf A}\put (5.2,3.1){\sf B}\put (5.2,-0.2){\sf C}\put (2.4,1){\sf O}\put (2,-0.4){\bf 50\:m}\put (-1,1.5){\sf 25\:m}\end {picture}](https://tex.z-dn.net/?f=%5Csetlength%7B%5Cunitlength%7D%7B1cm%7D%5Cbegin%7Bpicture%7D%280%2C0%29%5Cthicklines%5Cqbezier%20%280%2C0%29%280%2C0%29%285%2C0%29%5Cqbezier%20%280%2C0%29%280%2C0%29%280%2C3%29%5Cqbezier%20%280%2C3%29%280%2C3%29%285%2C3%29%5Cqbezier%20%285%2C3%29%285%2C3%29%285%2C0%29%5Cqbezier%20%280%2C3%29%285%2C0%29%285%2C0%29%5Cqbezier%20%280%2C0%29%280%2C0%29%285%2C3%29%5Cput%20%28-0.4%2C-0.2%29%7B%5Csf%20D%7D%5Cput%20%28-0.2%2C3.1%29%7B%5Csf%20A%7D%5Cput%20%285.2%2C3.1%29%7B%5Csf%20B%7D%5Cput%20%285.2%2C-0.2%29%7B%5Csf%20C%7D%5Cput%20%282.4%2C1%29%7B%5Csf%20O%7D%5Cput%20%282%2C-0.4%29%7B%5Cbf%2050%5C%3Am%7D%5Cput%20%28-1%2C1.5%29%7B%5Csf%2025%5C%3Am%7D%5Cend%20%7Bpicture%7D)
Length=50m
Breadth=25m
Diagonal be x
- It will form right angle triangle Like below
![\setlength{\unitlength}{1cm}\begin{picture}(6,5)\linethickness{.4mm}\put(1,1){\line(1,0){4.5}}\put(1,1){\line(0,1){3.5}}\qbezier(1,4.5)(1,4.5)(5.5,1)\put(.3,2.5){\large\bf 25m}\put(2.8,.3){\large\bf 50m}\put(1.02,1.02){\framebox(0.3,0.3)}\put(.7,4.8){\large\bf A}\put(.8,.3){\large\bf B}\put(5.8,.3){\large\bf C}\qbezier(4.5,1)(4.3,1.25)(4.6,1.7)\put(3.8,1.3){\large\bf $\Theta$}\end{picture}](https://tex.z-dn.net/?f=%5Csetlength%7B%5Cunitlength%7D%7B1cm%7D%5Cbegin%7Bpicture%7D%286%2C5%29%5Clinethickness%7B.4mm%7D%5Cput%281%2C1%29%7B%5Cline%281%2C0%29%7B4.5%7D%7D%5Cput%281%2C1%29%7B%5Cline%280%2C1%29%7B3.5%7D%7D%5Cqbezier%281%2C4.5%29%281%2C4.5%29%285.5%2C1%29%5Cput%28.3%2C2.5%29%7B%5Clarge%5Cbf%2025m%7D%5Cput%282.8%2C.3%29%7B%5Clarge%5Cbf%2050m%7D%5Cput%281.02%2C1.02%29%7B%5Cframebox%280.3%2C0.3%29%7D%5Cput%28.7%2C4.8%29%7B%5Clarge%5Cbf%20A%7D%5Cput%28.8%2C.3%29%7B%5Clarge%5Cbf%20B%7D%5Cput%285.8%2C.3%29%7B%5Clarge%5Cbf%20C%7D%5Cqbezier%284.5%2C1%29%284.3%2C1.25%29%284.6%2C1.7%29%5Cput%283.8%2C1.3%29%7B%5Clarge%5Cbf%20%24%5CTheta%24%7D%5Cend%7Bpicture%7D)
So
➝x^2=50^2+25^2
➝x=√(50)^2+(25)^2
➝x=√2500+625
➝x=√3125
➝x=55.9m
➝x=56m(approx)