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nlexa [21]
4 years ago
11

Estimate 23,945 + 46,718 by rounding to the highest place value.

Mathematics
1 answer:
kolbaska11 [484]4 years ago
4 0
The highest place value is in the ten thousand for both of these numbers. Let's round the two numbers first, and then we will add them. Let's round 23,945. So, we need to round to the ten thousand place, so we look at the number behind it (3) and act accordingly.
Remember:
5 or more? Raise the Score
4 or less? Let it Rest
We are looking at the bolded number: 23,945. This number is 4 or less, so we let it rest. So, the new rounded number is 20,000. 
Now let's look at 46,718. So, we need to round to the ten thousand place, so we look at the number behind it (6) and act accordingly. Look at the bolded number: 46,718. This number is 5 or more, so we raise the score. The new rounded number becomes 50,000.
Now, all you have to do is add 20,000+50,000, which is 70,000. Hope this helped!
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3 0
3 years ago
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Bingel [31]
Simplify the exponents
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7 0
3 years ago
Which of the following expressions are equivalent to 6 + (-4) - 5
Mila [183]

Answer:

B and C

Step-by-step explanation:

All you need to do is find the answer for all of them and see which ones match

Original:

6 + (-4) - 5

6 - 4 - 5

2 - 5

<u><em>-3</em></u>

This is the answer for the original expression, now we need to see which one is the correct match....

A. -(-6 + 4 ) - 5

2 negatives being subtracted gives you a positive

6 + 4 - 5

10 - 5

5

Incorrect, so now we know its not A

B. 6 - 4 - ( -5)

Again 2 negatives give you a positive

6 - 4 + (5)

6 - 9

-3

Correct, so now we know its B

C. 6 - (4 + 5)

PEMDAS so do the parenthesis first

6 - 9

-3

Correct, so now we it's C.

D. 6 + 4 - 56

10 - 56

-46

Incorrect, so now we know its not D

E. -(-6) + (-4) - (-5)

Again, 2 negatives equal a positive

6 - 4 + 5

2 + 5

7

Incorrect so now we know its not E

The correct answer is C

Hope this helped!

Have a supercalifragilisticexpialidocious day!

6 0
3 years ago
The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a st
Alinara [238K]

Answer:

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. The sum of the probabilities is decimal 1. So 1-pvalue is the probability that the value of the measure is larger than X.

In this problem

The line width used for semiconductor manufacturing is assumed to be normally distributed with a mean of 0.5 micrometer and a standard deviation of 0.05 micrometer, so \mu = 0.5, \sigma = 0.05.

What is the probability that a line width is greater than 0.62 micrometer?

That is P(X > 0.62)

So

Z = \frac{X - \mu}{\sigma}

Z = \frac{0.62 - 0.5}{0.05}

Z = 2.4

Z = 2.4 has a pvalue of 0.99180.

This means that P(X \leq 0.62) = 0.99180.

We also have that

P(X \leq 0.62) + P(X > 0.62) = 1

P(X > 0.62) = 1 - 0.99180 = 0.0082

There is a 0.82% probability that a line width is greater than 0.62 micrometer.

3 0
3 years ago
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