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german
3 years ago
7

THIS IS MY TEST IN GEOMETRY HELP

Mathematics
1 answer:
kenny6666 [7]3 years ago
6 0

Given:

Height of access ramp = 6 foot

Ramp ends at a point 40 feet away along the ground.

To find:

The angle of depression in nearest tenth of a degree.

Solution:

Using the given information, draw a figure as shown below.

In a right angle triangle,

\tan \theta = \dfrac{\text{Perpendicular}}{\text{Base}}

In triangle ABC,

\tan \theta=\dfrac{AB}{BC}

\tan \theta=\dfrac{6}{40}

\tan \theta=0.15

Taking tan inverse on both sides.

\theta=\tan^{-1}(0.15)

\theta=8.5307656

\theta \approx 8.5

Therefore, the angle of depression is 8.5 degrees.

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In standard form: (x+5)(3x-1)-(x-4)^2
denpristay [2]
I hope this helps you



x.3x+x.(-1)+5.3x+5.(-1)-(x^2-2.4.x+16)


3x^2-x+15x-5-x^2+8x-16


2x^2+22x-21
6 0
3 years ago
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Evaluate: 6.7 × $99.99 =<br> O $692.43<br> O $106.69<br> O $669.93<br> O $14.92
Lilit [14]
The answer is $669.93
7 0
2 years ago
Quick Answers Please
Rudik [331]

Then Nicolas would have:

4 and 1/16 of that one pizza

8 0
3 years ago
Alvin is 7 years younger than Elgas. The sum of their ages is 63. What is Elgas age?
Elden [556K]

Answer:

Elgas is 35.

Step-by-step explanation:

Let's set up an equation.

Alvin is 7 years younger than Elgas.

A = E - 7

The sum of their ages is 63.

A + E = 63

Let's use substitution.

Plug in the first equation of A into the second equation.

A + E = 63

(E - 7) + E = 63

Combine like terms.

2E - 7 = 63

Add 7 to both sides.

2E = 70

Divide both sides by 2.

E = 35

Elgas is 35.

Hope this helps!

6 0
3 years ago
An elementary school is offering 3 language classes: one in Spanish, one in French,and one in German. The classes are open to an
Alona [7]

Answer:

A. 0.5

B. 0.32

C. 0.75

Step-by-step explanation:

There are

  • 28 students in the Spanish class,
  • 26 in the French class,
  • 16 in the German class,
  • 12 students that are in both Spanish and French,
  • 4 that are in both Spanish and German,
  • 6 that are in both French and German,
  • 2 students taking all 3 classes.

So,

  • 2 students taking all 3 classes,
  • 6 - 2 = 4 students are in French and German, bu are not in Spanish,
  • 4 - 2 = 2 students are in Spanish and German, but are not in French,
  • 12 - 2 = 10 students are in Spanish and French but are not in German,
  • 16 - 2 - 4 - 2 = 8 students are only in German,
  • 26 - 2 - 4 - 10 = 10 students are only in French,
  • 28 - 2 - 2 - 10 = 14 students are only in Spanish.

In total, there are

2 + 4 + 2 + 10 + 8 + 10 +14 = 50 students.

The classes are open to any of the 100 students in the school, so

100 - 50 = 50 students are not in any of the languages classes.

A. If a student is chosen randomly, the probability that he or she is not in any of the language classes is

\dfrac{50}{100} =0.5

B. If a student is chosen randomly,  the probability that he or she is taking exactly one language class is

\dfrac{8+10+14}{100}=0.32

C. If 2 students are chosen randomly,  the probability that both are not taking any language classes is

0.5\cdot 0.5=0.25

So,  the probability that at least 1 is taking a language class is

1-0.25=0.75

3 0
4 years ago
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