Answer:
V0 = 48 feet per second is the answer.
Step-by-step explanation:
The given function which represents height of a golf ball in feet after x seconds after a player hits it.
y = -16x² + v0x
here v0 is the initial velocity and we have to calculate initial velocity. The ball returns to the ground 3 seconds after it is hit.
After 3 seconds height of the ball will be 0.
Now from the given function
0 = -16(3)² + v0×3
3v = 16×9
v0 = 16×9/3 = 48 feet per second.
D is the bast answer for this question, but, the equation should be (78-54)/3=p.
5x + 2(x + 1) ≤ 23
Distribute the 2.
5x + 2x + 2 ≤ 23
Combine like terms.
7x + 2 ≤ 23
Subtract 2 from both sides.
7x ≤ 21
Divide both sides by 7
x ≤ 3
9514 1404 393
Answer:
angles (W, X, Y) = (77°, 62°, 41°)
Step-by-step explanation:
<u>Given</u>:
ΔWZY
∠W = 2(∠Y) -5°
∠X = ∠Y +21°
<u>Find</u>:
∠X, ∠Y, ∠W
<u>Solution</u>:
Using angle measures in degrees, we have ...
∠X + ∠Y + ∠Z = 180
(∠Y +21) +∠Y + (2(∠Y) -5) = 180
4(∠Y) +16 = 180 . . . . . simplify
∠Y +4 = 45 . . . . . . . . . divide by 4
∠Y = 41 . . . . . . . . . . . . subtract 4
∠W = 2(41) -5 = 77
∠X = 41 +21 = 62
The angle measures of angles (W, X, Y) are (77°, 62°, 41°), respectively.
Answer:
y=30x+50 and y=40
Step-by-step explanation:
