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2 years ago

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Please help me on this

1 answer:

IrinaK [193]2 years ago

5 0

Babushka babushka babushka

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To celebrate ratios, Mrs. Johnson’s class will make pizzas. Julio is in charge of bringing in the sauce. There are 30 students i

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Answer:

Step-by-step explanation:

C

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3 years ago

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A coin is biased to show 39% heads and 61% tails. The coin is tossed twice. What is the probability that the coin turns up tails

julia-pushkina [17]

I'm pretty sure that this is a trick question, the answer is 61%.

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3 years ago

Given: ∠A is a straight angle. ∠B is a straight angle.

choli [55]

Given: ∠A is a straight angle. ∠B is a straight angle.

We need to Prove: ∠A≅∠B.

We know straight angles are of measure 180°.

So, ∠A and <B both would be of 180°.

It is given that ∠A and ∠B are straight angles. This means that <u>both angles are of 180°</u> because of the <u>the definition of straight angles</u>. Using <u>the definition of equality</u>, m∠A=m∠B . Finally, ∠A≅∠B by <u>definition of congruent. </u>

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3 years ago

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Which probability distribution table corresponds with this frequency distribution table

nlexa [21]

Answer:

A.

$\begin{array}{cccccc}x&1&2&3&4&5\\f&0.2&0.3&0.05&0.2&0.25\end{array}$

Step-by-step explanation:

First find the sum

$\sum f=4+6+1+4+5=20.$

Now, find the probabilities:

$Pr(x=1)=\dfrac{4}{20}=\dfrac{1}{5}=0.2;$
$Pr(x=2)=\dfrac{6}{20}=\dfrac{3}{10}=0.3;$
$Pr(x=3)=\dfrac{1}{20}=0.05;$
$Pr(x=4)=\dfrac{4}{20}=\dfrac{1}{5}=0.2;$
$Pr(x=5)=\dfrac{5}{20}=\dfrac{1}{4}=0.25.$

Hence, the frequency distribution table is

$\begin{array}{cccccc}x&1&2&3&4&5\\f&0.2&0.3&0.05&0.2&0.25\end{array}$

4 0

2 years ago

Suppose a football is kicked with an initial velocity of 82 ft/sec., at an angle of

satela [25.4K]

Answer:

The position P is:

$P = 87\^x + 75\^y$ ft <u><em> Remember that the position is a vector. Observe the attached image</em></u>

Step-by-step explanation:

The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity $s_0$ is:

$y(t) = y_0 + s_0t -16t ^ 2$

Where $y_0$ is the initial height = 0 for this case

We know that the initial velocity is:

82 ft/sec at an angle of 58 ° with respect to the ground.

So:

$s_0 = 82sin(58\°)$ ft/sec

$s_0 = 69.54$ ft/sec

Thus

$y(t) = 69.54t -16t ^ 2$

The height after 2 sec is:

$y(2) = 69.54 (2) -16 (2) ^ 2$

$y(2) = 75\ ft$

Then the equation that describes the horizontal position of the ball is

$X(t) = X_0 + s_0t$

Where

$X_ 0 = 0$ for this case

$s_0 = 82cos(58\°)$ ft / sec

$s_0 = 43.45$ ft/sec

So

$X(t) = 43.45t$

After 2 seconds the horizontal distance reached by the ball is:

$X (2) = 43.45(2)\\\\X (2) = 87\ ft$

Finally the vector position P is:

$P = 87\^x + 75\^y$ ft

6 0

3 years ago