Answer:
The number that cannot be the largest possible 6-digit number is;
(D) AAABCB
Step-by-step explanation:
From the question, we have;
A, B, and C = Distinct digits, therefore, A ≠ B ≠ C
The number of digits in the number to be formed = 6 digits
The number of 'A' in the number to be formed = 3
The number of 'B' in the number to be formed = 2
The number of 'C' in the number to be formed = 1
We have;
When A > B > C
The largest possible number = AAABBC
When C > A > B
The largest possible number = CAAABB
When B > A > C
The largest possible number = BBAAAC
When A > C > B
The largest possible number = AAACBB
Therefore, given that when A > B > C, the largest possible number = AAABBC, we have;
AAABBC > AAABCB, because B > C, therefore, within the tens and unit of the two 6 digit numbers, we have, BC > CB
∴ AAABBC > AAABCB and <u>AAABCB</u>, cannot be the largest possible 6-digit number
