Answer:
you cant round that to 30
Step-by-step explanation
29.20
29.2 2 is less than 5
so you cant round you can only round if the .tens place is 5 or more
Step-by-step explanation:
please mark me as brainlest
The x-y coordinates for the given equation are: (-2,11),(-1,7),(0,3), (1,-1) and (2,-5).
<h3>Linear Function</h3>
A linear function can be represented by a line. The standard form for this equation is: ax+b , for example, y=2x+7. Where:
- a= the slope;
- b=the constant term that represents the y-intercept.
The given equation is 16x + 4y = 12. For solving this question, you should replace the given values of x for finding the values of y.
Thus,
- For x= -2, the value of y will be:
16*(-2)+4y=12
-32+4y=12
4y=12+32
4y=44
y=11
- For x= -1, the value of y will be:
16*(-1)+4y=12
- -16+4y=12
- 4y=12+16
- 4y=28
- y=7
- For x= 0, the value of y will be:
16*(0)+4y=12
- For x= 1, the value of y will be:
16*(1)+4y=12
- 16+4y=12
- 4y=12-16
- 4y=-4
- y= -1
- For x= 2, the value of y will be:
16*(2)+4y=12
- 32+4y=12
- 4y=12-32
- 4y=-20
- y= -5
Read more about the linear equation here:
brainly.com/question/1884491
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Answer:
B. 21.2
Step-by-step explanation:
Perimeter of ∆ABC = AB + BC + AC
A(-4, 1)
B(-2, 3)
C(3, -4)
✔️Distance between A(-4, 1) and B(-2, 3):




AB = 4 units
✔️Distance between B(-2, 3) and C(3, -4):




BC = 8.6 units (nearest tenth)
✔️Distance between A(-4, 1) and C(3, -4):




AC = 8.6 units (nearest tenth)
Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units
Parallel = same slope
Y = -3x + 7, the slope is -3
Slope intercept form: y = mx + b
Y = -3x + b
Plug in point (2,-4) and solve for b
-4 = -3(2) + b
-4 = -6 + b, b = 2
Solution: y = -3x + 2
The answer is D