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Dovator [93]
3 years ago
8

49^-1/2 • 64^2/3Express answer in simplest form (show work plz)​

Mathematics
1 answer:
galben [10]3 years ago
7 0

~Hello There!~

Anything to a negative power, turns it into 1 over that number.

Therefore 49^{-\frac{1}{2} }  = \frac{1}{49\frac{1}{2} }

Anything to the power of a half, means you have to square root it.

Therefore, the first part is now \frac{1}{7}

When you have a fraction as a power and both numbers are above one:

You must 'root' it by the denominator and put it to the power of the top number.

Therefore, \sqrt[3]{64} = 4

4^{2} = 16

Now we have:

\frac{1}{7} * 16

Simply divide 16 by 7 to get the answer:

2.285714

However, since it is a long number, you can just leave it as \frac{16}{7}

Hope This Helps You!                                                                                      

Good Luck :)                                                                                                      

Have A Great Day ^_^

- Hannah ❤

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Step-by-step explanation:

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3 years ago
A line passes through the points (0, 9) and (9, 19). What is its equation in slope-intercept form?
STatiana [176]

Answer:

y = 10/9x + 9

Step-by-step explanation:

To write the equation in its slope-intercept form, y = mx + b, we need to find the slope (m) of the line and its y-intercept (b).

Given the points (0, 9) and (9, 19), we can solve for the slope of the line using the following formula:

m = \frac{y2 - y1}{x2 - x1}

Let (x1, y1) = (0, 9)

and (x2, y2) = (9, 19)

Substitute these values on the formula:

m = \frac{y2 - y1}{x2 - x1} = \frac{19 - 9}{9 - 0} = \frac{10}{9}

Therefore, the slope (<em>m </em>) = 10/9.

Next, the <u>y-intercept</u> is the point on the graph where it crosses the y-axis, and has the coordinates, (0, <em>b </em>). It is also the value of the y when x = 0.

One of the given points is the y-intercept of the line, given by (0, 9). The y-coordinate, 9, is the value of b.

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3 0
2 years ago
In 3-4 sentences, describe how you would find a line parallel to the line 2x + 5y = 15 that goes through the point (-10, 1). Be
larisa86 [58]

the parallel line is 2x+5y+15=0.

Step-by-step explanation:

ok I hope it will work

soo,

Solution

given,

given parallel line 2x+5y=15

which goes through the point (-10,1)

now,

let 2x+5y=15 be equation no.1

then the line which is parallel to the equation 1st

2 x+5y+k = 0 let it be equation no.2

now the equation no.2 passes through the point (-10,1)

or, 2x+5y+k =0

or, 2*-10+5*1+k= 0

or, -20+5+k= 0

or, -15+k= 0

or, k= 15

putting the value of k in equation no.2 we get,

or, 2x+5y+k=0

or, 2x+5y+15=0

which is a required line.

6 0
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creativ13 [48]

Answer:

\frac{2}{15}  {cm}^{2}

Step-by-step explanation:

Area of Rectangle = Length x Breadth

=

\frac{1}{5}  \times  \frac{2}{3}  \\  =  \frac{2}{15}  {cm}^{2}

4 0
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