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ollegr [7]
3 years ago
15

Analyze the code and identity the value of variable a,b and c after the code execution. int a=40, b=50, c=60; if(! (a>=40)) b

=30; c=70; A. A = 40, b = 50, c = 70 B. A = 40, b = 30, c = 70 C. A = 40, b = 50, c = 60 Da = 40, b = 30, c = 60
Computers and Technology
1 answer:
AlekseyPX3 years ago
7 0

Answer:

a=40,b=30,c=60

The answer is B

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<span>The finished product is "output." In the electronic computer, data are the raw material or input to the computer.</span>
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Group of answer choices When declaring a variable, you also specify the type of its values. Variables cannot be assigned and dec
olga nikolaevna [1]

Complete Question:

Which of the following statement is true?

Group of answer choices.

A. When declaring a variable, you also specify the type of its values.

B. Variables cannot be assigned and declared in the same statement.

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D. Variable names must contain at least one dollar sign.

Answer:

A. When declaring a variable, you also specify the type of its values.

Explanation:

In Computer programming, a variable can be defined as a placeholder or container for holding a piece of information that can be modified or edited.

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\\parameter Name as Type (Keywords) = value;

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6 0
2 years ago
Find the inverse function of f(x)= 1+squareroot of 1+2x
Svetllana [295]

Answer:

Therefore the inverse function of  f(x)=1+\sqrt{1+2x} is \frac{x^2-2x}{2}

Explanation:

We need to find the inverse of function f(x)=1+\sqrt{1+2x}

Function Inverse definition :

\mathrm{If\:a\:function\:f\left(x\right)\:is\:mapping\:x\:to\:y,\:then\:the\:inverse\:functionof\:f\left(x\right)\:maps\:y\:back\:to\:x.}

y=1+\sqrt{1+2x}\mathrm{Interchange\:the\:variables}\:x\:\mathrm{and}\:y

x=1+\sqrt{1+2y}

\mathrm{Solve}\:x=1+\sqrt{1+2y}\:\mathrm{for}\:y

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

1+\sqrt{1+2y}-1=x-1

Simplify

\sqrt{1+2y}=x-1

\mathrm{Square\:both\:sides}

\left(\sqrt{1+2y}\right)^2=\left(x-1\right)^2

\mathrm{Expand\:}\left(\sqrt{1+2y}\right)^2:\quad 1+2y

\mathrm{Expand\:}\left(x-1\right)^2:\quad x^2-2x+1

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\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

1+2y-1=x^2-2x+1-1

\mathrm{Simplify}

2y=x^2-2x

\mathrm{Divide\:both\:sides\:by\:}2

\frac{2y}{2}=\frac{x^2}{2}-\frac{2x}{2}

\mathrm{Simplify}

y=\frac{x^2-2x}{2}

Therefore the inverse function of f(x)=1+\sqrt{1+2x} is \frac{x^2-2x}{2}

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kakasveta [241]

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Explanation:

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conduction

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The handle will warm up until it's total heat losses equal the total heat coming in. Heat comes in mostly by conduction from the body of the pot.

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