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Tems11 [23]
3 years ago
5

Given an integer n and an array a of length n, your task is to apply the following mutation to an: Array a mutates into a new ar

ray b of length n.
For each i from 0 to n - 1, b[i] = a[i - 1] + a[i] + a[i + 1].
If some element in the sum a[i - 1] + a[i] + a[i + 1] does not exist, it should be set to 0. For example, b[0] should be equal to 0 + a[0] + a[1].
Computers and Technology
1 answer:
Elenna [48]3 years ago
3 0

Answer: provided in the explanation section

Explanation:

import java.util.*;

class Mutation {

public static int[] mutateTheArray(int n , int[] a)

{

int []b = new int[n];

for(int i=0;i<n;i++)

{

b[i]=0;

if(((i-1)>=0)&&((i-1)<n))

b[i]+=a[i-1];

if(((i)>=0)&&((i)<n))

b[i]+=a[i];

if(((i+1)>=0)&&((i+1)<n))

b[i]+=a[i+1];

}

return b;

}

  public static void main (String[] args) {

      Scanner sc = new Scanner(System.in);

      int n= sc.nextInt();

      int []a = new int [n];

     

      for(int i=0;i<n;i++)

      a[i]=sc.nextInt();

     

      int []b = mutateTheArray(n,a);

for(int i=0;i<n;i++)

      System.out.print(b[i]+" ");

     

 

     

  }

}

cheers i hope this helped !!

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<h2>Answer:</h2>

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public class FirstAndLast{

   //Begin the main method

    public static void main(String []args){

       

       

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    }  // end of main method

   

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<h2>Explanation:</h2>

The code has been written in Java and it contains comments explaining important parts of the code. Kindly go through the comments.

The source code and a sample output have also been attached to this response.

To run this program, copy the code in the source code inside a Java IDE or editor and save it as FirstAndLast.java

Download java
<span class="sg-text sg-text--link sg-text--bold sg-text--link-disabled sg-text--blue-dark"> java </span>
4c53f66d970acf88b251b2cf41bcdaf6.png
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