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3 years ago

Determine which of the following sequences is arithmetic. If the sequence is arithmetic, determine the first term a, an

Mathematics

1 answer:

Ilya [14]3 years ago

7 0

Answer:

the sequence is arithmetic with first term 2 and common different is 2

Step-by-step explanation:

please give me brainlest

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Help me plz and explain your answer to me

Vlad1618 [11]

Answer:

$4.171\times10^6$

Step-by-step explanation:

Given:

First Number = 97

Second Number = $4.3\times10^4$

We need to find the product of two numbers in Scientific notation.

Product of two numbers means we need to multiply two number.

Also The proper format for scientific notation is a x 10^b where a is a number or decimal number such that the absolute value of a is less than ten and is greater than or equal to one or, 1 ≤ |a| < 10. b is the power of 10 such that the scientific notation is mathematically equivalent to the original number.

Decimal points are moved until there is only one non-zero digit to the left of the decimal point. The decimal number results as a.

Number of decimal point moved needs to be counted. This number is b.

If decimal are moved to the left b is positive.

If decimal are moved to the right b is negative.

If decimal are not moved b = 0.

scientific notation of a number can be written as a x 10^b and read it as "a times 10 to the power of b."

Hence the product is;

$97\times4.3\times 10^4 = 417.1 \times 10^4$

Expressing in Scientific Notation form we get

$4.171 \times 10^6$

Hence the Answer is $4.171 \times 10^6$ .

3 0

3 years ago

Hannah has 67.32 centimeters of wire. She uses 2 pieces of the wire.

mojhsa [17]

Answer:

38.46 (Rounded: 38.5)

Step-by-step explanation:

67.32-2(14.43)=38.46

3 0

4 years ago

<img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%5E%7B2%7D-5x%2B6%7D%7B2x%5E%7B2%7D-7x%2B6%20%7D" id="TexFormula1" title="\frac{x^{

il63 [147K]

Answer:

$\frac{x-3}{2x-3}$ . hole or removable discontinuity at x=2

Step-by-step explanation:

Well generally if you want the simplest form, you factor each the denominator and numerator and then see if you can cancel any of the factors out (because they're in the denominator and numerator)

So let's start by factoring the first equation:

$x^2-5x+6$

Now let's find what ac is (it's just c since a=1...)

$AC= 6$

List factors of -6

$\pm1, \pm2, \pm3, \pm6$ .

Now we have to look for two numbers that add up to -5. It's a bit obvious here since there isn't many factors, but it's -2 and -3, and they're both negative since 6 is positive, and -5 is negative...

So using these two factors we get

$(x-2)(x-3)$

Ok now let's factor the second equation:

$2x^2-7x+6$

Multiply a and c

$AC = 12$

List factors of 12:

$\pm1, \pm2, \pm3, \pm4, \pm6, \pm12$ .

Factors that add up to -7 and multiply to 12:

$-3\ and\ -4$

Rewrite equation:

$2x^2-4x-3x+6$

Group terms:

$(2x^2-4x)+(-3x+6)$

Factor out GCF:

$2x(x-2)-3(x-2)$

Rewrite:

$(2x-3)(x-2)$

Now let's write out the equation using these factors:

$\frac{(x-2)(x-3)}{(2x-3)(x-2)}$ .

Here we can factor out the x-2 and the simplified form is:

$\frac{x-3}{2x-3}$

So we can "technically" define f(2) using the most simplified form, but it's removable discontinuity, so it has a hole as x=2. since it makes (x-2) equal to 0 (2-2) = 0.

8 0

2 years ago

Find the length of QT if Q is between M and T, if MT=18.3 and MQ=7.8

creativ13 [48]

Answer: QT= 10.5

Step-by-step explanation:

18.3-7.8

8 0

3 years ago

A scientist runs an experiment involving a culture of bacteria. She notices that the mass of the bacteria in the culture increas

Genrish500 [490]

The growth factor for the mass of bacteria is 2.8 in 1 week.

Step-by-step explanation:

Step 1:

It is given that the bacteria in the culture increase by 260% per week. Now we assign values to get a better understanding. If there were 1,000 bacteria in the culture at the start of the week there would be 1,000 + 260% at the week's end = 1,000 + 2,600 = 3,600 at the week's end.

Step 2:

To calculate the growth factor, we calculate the difference between the present value and the past value and divide it by the past value.

Here the past value is 1,000 and the present value is 2,600.

Growth factor = $\frac{difference in values}{past value} = \frac{3,600-1,000}{1000} = \frac{2,600}{1,000} = 2.6.$

So the growth factor is 2.6 per week.

7 0

3 years ago