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lbvjy [14]
3 years ago
12

PLS HELP WILL GIVE BRIANLEST.

Mathematics
1 answer:
satela [25.4K]3 years ago
6 0

Answer:

In this equation, let "x" equal the rate at which the tub will be filled. The tub holds 32 gallons, which will be one half of the equation. The tub already contains 12 gallons, so this will be half of the other side of the equation. The rate is "x" gallons per minute, and the time it required was 5 minutes, so this would be "5x". Placing all these parts together gives an equation of (32 = 5x + 12) gallons per minute dispensed.

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Help i'm confused.....
AlladinOne [14]

Answer:

the fourth one 2(4+n)

Step-by-step explanation:

you do 4+n

whatever the sum is you multiply that by 2

lmk if that helps

5 0
2 years ago
3(4a+7)=5(2a+4)+1 What is it?
hichkok12 [17]

Answer:

a = 0

Step-by-step explanation:

3(4a+7)=5(2a+4)+1     Distribute 3 through the parentheses

                 - >                         12a + 21 = 5(2a + 4) +1

5(2a + 4) +1   -->  10a + 20 + 1

12a + 21 = 10a + 20 + 1  -->    12a + 21 = 10a + 21   -->      12a = 10a

                                                     12a - 10a = 0   -->    2a = 0

Divide both sides of the equation by 2      -->     a = 0

7 0
3 years ago
A bicycle wheel makes five rotations. The bicycle travels 43.18 ft. Find the diameter of the wheel in inches. Use 3.14 for π.
Law Incorporation [45]

Answer:

Step-by-step explanation:

x=5c, c=3.14d

x=5(3.14)d

d=x/15.7, x=43.18ft

d=43.18/15.7

d=2.75ft

4 0
2 years ago
G
Svetllana [295]

Answer:

15

Step-by-step explanation:

since there is 7 teams and 12 can be the minimum we can do 7 x 12=84

this means that 3 people could possibly be on one single team.

the maximum number is 12+3=15

5 0
2 years ago
Find a cubic function f(x) = ax3 + bx2 + cx + d that has a local maximum value of 3 at x = −3 and a local minimum value of 0 at
Amiraneli [1.4K]

Answer:

The cubic function is f(x) = (27/32)·x  - 3/32·x³ - -9/32·x² - 9/32

Step-by-step explanation:

The given function is f(x) = a·x³ + b·x² + c·x + d

By differentiation, we have;

3·a·x² + 2·b·x + c = 0

3·a·(-3)² + 2·b·(-3) + c = 0

3·a·9 - 6·b + c = 0

27·a - 6·b + c = 0

3·a·(1)² + 2·b·(1) + c = 0

3·a + 2·b + c = 0

a·(-3)³ + b·(-3)² + c·(-3) + d = -3

-27·a + 9·b - 3·c + d = -3...(1)

a + b + c + d = 0...(2)

Subtracting equation (1) from equation (2) gives;

28·a - 8·b + 4·c = 3

Therefore, we have;

27·a - 6·b + c = 0

3·a + 2·b + c = 0

28·a - 8·b + 4·c = 0

Solving the system of equations using an Wolfram Alpha gives;

a = -3/32, b = -9/32, c = 27/32 from which we have;

a + b + c + d = 0 3 × (-3/32) + 2 × (-9/32) + (27/32) + d = 0

d = 0 - (0 3 × (-3/32) + 2 × (-9/32) + (27/32)) = -9/32

The cubic function is therefore f(x) = (-3/32)·x³ + (-9/32)·x² + (27/32)·x + (-9/32).

4 0
2 years ago
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