Question

Show that ab =2redecele 10​

Answer 1

Answer:

Step-by-step explanation:

1)

$AB^2 = BD^2 + AD^2$                 ------- ( 1 )

     $= 4^2 + (2\sqrt6)^2\\\\=16 + (4 \times 6)\\\\= 16 + 24\\\\= 40$

$AB = \sqrt {40} = \sqrt {4 \times 10} = 2\sqrt{10}$

2)

$AC^2 = AD^2 + DC^2$              --------------( 2 )

     $=(2 \sqrt6)^2 + 6^2 \\\\= 24 + 36\\\\=60$

$AC= \sqrt{60} = \sqrt{4 \times 15} = 2 \sqrt{15}$

3)

BC² = AB² + AC²

(4 + 6)²  = 40 + 60

100 = 100

Satisfies Pythagoras Theorem, therefore triangle ABC is right angles triangle.