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Sveta_85 [38]
3 years ago
8

9. YOU BE THE TEACHER Your friend

Mathematics
1 answer:
Crank3 years ago
8 0

Answer:

Step-by-step explanation:

Yes, it's reasonable.

What you are doing is solving the question by rounding. You come up with an answer. Suppose you loose the decimal somewhere and you get 0.36? Is that reasonable? Do you just write the answer in the provided blank and move on. What now?

You get it wrong?!!

But your estimate should be about 9/3 = 3. Now you look at your calculator with great misgivings, because it made a mistake. Did it or did you? Well ultimately you did, but you have to blame something. So the calculator takes the heat.

Who  knows? Maybe the decimal doesn't work. It's stuck or something. In any event you should be aware that there's no way the answer could be 0.36 when you estimate it to be 3.

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I don’t understand this
Lunna [17]

Answer:

it means that

y–x+6.8= 7.2–(–2)+6.8

–(–) will change into +

=7.2+2+6.8

=7.2+2.0+6.8

=16

<h2><em>hope</em><em> </em><em>u</em><em> </em><em>understood</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em></h2>

<em>Please</em><em> </em><em>mark</em><em> </em><em>me</em><em> </em><em>as</em><em> </em><em>Brainliest</em><em> </em>

3 0
4 years ago
How can i find The function of f(x) = 150 (1.3)^t
natka813 [3]

Answer:

See below.

Step-by-step explanation:

In comments, you said you wanted it graphed.

If it says f(x) on the left side, the equation should have an 'x' on the right side, so something is fishy here.

But, in an effort to try and help you ....

With the data you have given, I would graph it just like y = 150 (1.3)^x

You can pick various values for x, like -3,-2,-1,0,1,2,3 and see what y is for each one, then plot the points on graph paper.

If x = 0, y= 150(1.3)^0 = 150(1) = 150  because anything to power zero is 1

If x = -1, y= 150(1.3)^(-1) = 150(1/1.3) ≈ 132.7

If x = +1, y= 150(1.3)^(1) = 150(1.3) = 195

And so on.

I did the graph on DESMOS and it has a very large scale.

4 0
3 years ago
The function h represents the height of an object t seconds after it is launched into the air. The function is
nasty-shy [4]

Step-by-step explanation:

h(t) = -5t² + 20t + 18

this is a parabola (the curve an object follows when thrown up into the air and then falling back down).

and as such it will most likely have 2 solutions (one for when going up, and one for when falling back down again).

33 = -5t² + 20t + 18

15 = -5t² + 20t

-3 = t² - 4t

t² - 4t + 3 = 0

the solution of such a quadratic equation is

t = (-b ±sqrt(b² - 4ac))/(2a)

in our case

a = 1

b = -4

c = 3

t = (4 ±sqrt(16 - 4×1×3))/(2×1) = (4 ±sqrt(16-12))/2 =

= (4 ±sqrt(4))/2 = (4 ± 2)/2

t1 = (4+2)/2 = 6/2 = 3

t2 = (4-2)/2 = 2/2 = 1

the object reaches the height of 33 m first after 1 second (while going up), and then again after 3 seconds (while falling down again).

7 0
3 years ago
The product shown is a difference of squares. What is the missing constant term in the second factor?
34kurt
Difference of two squares is of the form (a + b)(a - b) or vice-versa. Here, a = -5x and b = 3.
(-5x - 3)(-5x + 3)
Answer: 3
7 0
3 years ago
Read 2 more answers
Translations and reflections
Liono4ka [1.6K]

Answer:

The answer is A. x + 5, y - 2

Step-by-step explanation:

The answer is A because you would move the block 5 spaces to the right and 2 spaces down.

Hope this helps!

5 0
3 years ago
Read 2 more answers
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