I’m totally confused can someone please help me!!!

Mathematics

2 answers:

german3 years ago

3 0

The second answer is right

Margaret [11]3 years ago

3 0

The answer is m = 2t.

To find this, you need to look at any given point and look at the t and m.

For example, when you look at t = 4, you see that m = 8.

Same thing for when t = 6, m =12.

To get m, you need to multiply each t by 2 which is where you get the equation m = 2t.

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Please help find domain and range

Oxana [17]

<h3>Answer: Choice A</h3>

Domain: x > 4
Range: y > 0

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Explanation:

We want to avoid having a negative number under the square root. Solving $x-4 \ge 0$ leads to $x \ge 4$

So it appears the domain could involve x = 4 itself; however, if we tried that x value, then we'd get a division by zero error.

So in reality, the domain is x > 4.

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The range of y = sqrt(x) is the set of positive real numbers. So y > 0 is the range for this equation. Shifting left and right does not affect the range, so the range of y = sqrt(x-4) is also y > 0.

We are dividing a positive number (3) over some positive number in the denominator. Overall, the expression $\frac{3}{\sqrt{x-4}}$ is positive because positive/positive = positive.

Therefore, the range of the given equation is y > 0

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The graph is shown below. We have a vertical asymptote at x = 4 and a horizontal asymptote at y = 0. The green curve is fenced in the upper right corner (northeast corner).