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Hitman42 [59]
3 years ago
6

I need help solving this problem. Thanks

Mathematics
1 answer:
max2010maxim [7]3 years ago
7 0

9514 1404 393

Answer:

  f = 2T/(v1 +v2)

Step-by-step explanation:

Multiply by the inverse of the coefficient of f.

  T=f\cdot\dfrac{v_1+v_2}{2}\\\\f=\dfrac{2T}{v_1+v_2}

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√18

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I need help ASAP which of the following is the inverse
mihalych1998 [28]

Answer:

The inverse of y=3ˣ is ㏒₃(x)

Step-by-step explanation:

change 3^x to Logarithmic form. the Log base is 3 because it's the base of the y=3ˣ , ㏒₃ the exponent in the ( ) in this case x. End up having ㏒₃x. then Graph both equations  on the same graph the two graphs should be reflections of each other over the y=x line.

I hope this helps you

6 0
4 years ago
What is the value of x in the proportion StartFraction 6 x plus 1 over 7 EndFraction equals StartFraction 18 x minus 2 over 14 E
Phoenix [80]
The correct answer is:  [C]:  " two-thirds <span>" .
</span>____________________________________________________
" x = " \frac{2}{3} " ; which is:  " two-thirds " .
____________________________________________________
Explanation:
____________________________________________________

Given:  " \frac{6x + 1}{7} = \frac{18x-2}{14} " ;  Solve for "x" ; 
____________________________________________________
First, multiply the first fraction by "\frac{2}{2}" ;  
   { since: "\frac{2}{2} = 1" ; and since any value, multiplied by "1" results in that exact same value.  By multiplying the first fraction by:                   "\frac{2}{2}" , we can get the "denominator" in the first fraction equal to the "denominator" of the second fraction.

→ \frac{2}{2}*( \frac{6x + 1}{7})=\frac{2(6x+1)}{2(7)} = \\    "\frac{2(6x+1)}{14}" .
___________________________________________________________
Note the "distributive property of multiplication" :
_______________________________________________________
  a(b + c)  = ab  + ac ; 

  a(b – c)  = ab – ac .
_______________________________________________________
As such, take the "numerator" ; which is:

" 2(6x + 1) " ;  and expand:

→  =  (2*6x) + (2*1) =  " 12x + 2 " ;

Now, we can rewrite the entire expression:
________________________________________
    "\frac{12x+2}{14}"  ;  and we can rewrite the entire equation:
________________________________________

→  " \frac{12x+2}{14} = \frac{18x-2}{14} [/tex] " ;

Let us simplify this:  " 12x + 2 = 18x – 2 " ;  Solve for "x" ;
_____________________________________________________
   
  →  18x – 2 = 12x + 2 ; 

  →  Subtract "12x" from each side of the equation; and subtract "2" from each side of the equation:


  →  18x – 2 – 12x – 2 = 12x + 2 – 12x – 2 ; 

to get: 

       →  6x – 4 = 0  ; 

Add "4" to each side of the equation:

       →  6x – 4 + 4 = 0 + 4 ; 

to get:

       →  6x = 4  ;

Divide each side of the equation by "6" ;
  to isolate "x" on one side of the equation; & to solve for "x" ; 

→ 6x / 6  = 4 / 6  ;

→  x = 4/6 ;   → "4/6" = "(4÷2)/(6÷2)" = "2/3" .

→  x = 2/3 ;   →  x = " \frac{2}{3} " ;  which is "two-thirds" ; 
         
                                            →  which is:  Answer choice:  [C]:  "<span> two-thirds</span><span>" .
</span>__________________________________________________________
3 0
3 years ago
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