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4 years ago

Each school day, Aidon wolks 11 blocks to school after school, he wolks 4 blocks to the library

Mathematics

1 answer:

Inga [223]4 years ago

5 0

Answer:

189

Step-by-step explanation:

Aidon walked 11 blocks to begin with than he walks 4 blocks to the library and 12 blocks home. This mean we add 11+4+12=27 and a week has 7 days which means we need to multiply that by 7 which gives us the product of 189.

Also, i double checked

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Find the area of the region that lies inside the first curve and outside the second curve.

marishachu [46]

Answer:

Step-by-step explanation:

From the given information:

r = 10 cos( θ)

r = 5

We are to find the the area of the region that lies inside the first curve and outside the second curve.

The first thing we need to do is to determine the intersection of the points in these two curves.

To do that :

let equate the two parameters together

So;

10 cos( θ) = 5

cos( θ) = $\dfrac{1}{2}$

$\theta = -\dfrac{\pi}{3}, \ \ \dfrac{\pi}{3}$

Now, the area of the region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e

$A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} (10 \ cos \ \theta)^2 d \theta - \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ 5^2 d \theta$

$A = \dfrac{1}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} 100 \ cos^2 \ \theta d \theta - \dfrac{25}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \ \ d \theta$

$A = 50 \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix} \dfrac{cos \ 2 \theta +1}{2} \end {pmatrix} \ \ d \theta - \dfrac{25}{2} \begin {bmatrix} \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}}$

$A =\dfrac{ 50}{2} \int \limits^{\dfrac{\pi}{3}}_{-\dfrac{\pi}{3}} \begin {pmatrix} {cos \ 2 \theta +1} \end {pmatrix} \ \ d \theta - \dfrac{25}{2} \begin {bmatrix} \dfrac{\pi}{3} - (- \dfrac{\pi}{3} )\end {bmatrix}$

$A =25 \begin {bmatrix} \dfrac{sin2 \theta }{2} + \theta \end {bmatrix}^{\dfrac{\pi}{3}}_{\dfrac{\pi}{3}} \ \ - \dfrac{25}{2} \begin {bmatrix} \dfrac{2 \pi}{3} \end {bmatrix}$

$A =25 \begin {bmatrix} \dfrac{sin (\dfrac{2 \pi}{3} )}{2}+\dfrac{\pi}{3} - \dfrac{ sin (\dfrac{-2\pi}{3}) }{2}-(-\dfrac{\pi}{3}) \end {bmatrix} - \dfrac{25 \pi}{3}$

$A = 25 \begin{bmatrix} \dfrac{\dfrac{\sqrt{3}}{2} }{2} +\dfrac{\pi}{3} + \dfrac{\dfrac{\sqrt{3}}{2} }{2} + \dfrac{\pi}{3} \end {bmatrix}- \dfrac{ 25 \pi}{3}$

$A = 25 \begin{bmatrix} \dfrac{\sqrt{3}}{2 } +\dfrac{2 \pi}{3} \end {bmatrix}- \dfrac{ 25 \pi}{3}$

$A = \dfrac{25 \sqrt{3}}{2 } +\dfrac{25 \pi}{3}$

The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.

Download docx

7 0

3 years ago

Find the distance between (3,-6) and (2,-4). please help

Advocard [28]

Answer:

$\sqrt{99}$

Step-by-step explanation:

you can use the distance formula to find the distance between two given points.

the distance formula is:

$d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}$

so if you simply plug in you get:

$d = \sqrt{(2 - 3)^2 + (-4-(-6))^2}$

simplify

$d = \sqrt{(-1)^2 + (-10)^2}\\$

simplify again

$d = \sqrt{-1 + 100}\\$

and again

$d = \sqrt{99}\\$

and you have an answer

5 0

4 years ago

A freight train is carrying goods across the country. The number of gallons of fuel it has used varies directly with the distanc

Maru [420]

Answer:

0.125 miles per gallon.

Step-by-step explanation:

After 200 gallons used the freight train has traveled 25 miles. This means that we need to divide both sides by 200 to get a singular gallon's worth of miles traveled. 200/200 is 1, and 25/200 is 0.125.

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Extra

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IF it were how many gallons per mile, you would divide both answers by 25 resulting in 8 gallons per mile.

6 0

4 years ago

Read 2 more answers

Use a number line to name two numbers that are the same distance apart as 3.2 and 4.4.

Nataliya [291]

Answer:

3.3 and 4.5

Step-by-step explanation: