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Natali5045456 [20]
3 years ago
5

(3,-8), (3, 2), (6, -1), (2, 2)) (-6, 3), (2,-2), (0, 8), (1, 1))

Mathematics
1 answer:
77julia77 [94]3 years ago
5 0

Answer:

yeet

Step-by-step explanation:

yeet

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ExtremeBDS [4]
29 dimes
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Inverse laplace of [(1/s^2)-(48/s^5)]
Katen [24]
**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform F(s) and G(s), then \mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}

Given that \dfrac{1}{s^2} = \dfrac{1!}{s^2} and -\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}

From Table of Laplace Transform, you have \mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}} and hence \mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n

So you have \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}.

Hope this helps...
7 0
3 years ago
Determine whether the system of linear equations has one and only one solution, infinitely many solutions, or no solution. 2x −
zloy xaker [14]

Answer:

  • Only one solution
  • (x, y) = (-0.8, -3.6)

Step-by-step explanation:

You know there is only one solution because the ratio of x- and y-coefficients is different in the two equations. That means the lines will have different slopes, so must intersect in exactly one point.

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The y-coefficients are opposites, so you can eliminate the y-variable by adding the equations:

  (2x -y) + (3x +y) = (2) + (-6)

  5x = -4

  x = -4/5 = -0.8

Substituting this into the second equation, we have ...

  3(-0.8) +y = -6

  y = -3.6 . . . . . . . add 2.4 to both sides

The solution is (x, y) = (-0.8, -3.6).

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You can also find the solution by graphing (or using a graphing calculator).

5 0
3 years ago
What is the circumference of circle P?<br> Express your answer in terms of pi.<br><br> PC= 17 cm.
Sedbober [7]
I am assuming that PC is a radius.

d = 2 * PC = 2 * 17 = 34

C = pi * d
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if PC is a diameter, the change the 34 into 17.
3 0
4 years ago
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2 1/3 fills 3 1/2 dispensers how many fill one
Y_Kistochka [10]

2/3 (0.666) quantities fills one dispenser.

Step-by-step explanation:

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2 1/3 we multiply the 2 with the 3 and add it with 1 while denominator remains 3, so 2 1/3 becomes 7/3. Similarly the fraction 3 1/2 converts into 7/2.

Step 2; So we have 7/3 quantities of liquid fills 7/2 dispensers. We multiply both sides by 2/7 so that the right side of the equation becomes 1 and the left side of the equation indicates the amount of liquid in 1 dispenser.

7/3 * 2/7 = 7/2 * 2/7 , 14/21 = 1 dispenser. So 14/21 = 2/3. So 2/3 or 0.666 quantity of liquid fills one dispenser.

8 0
3 years ago
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