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Yuki888 [10]
3 years ago
10

I need to k what are the answers to this

Mathematics
1 answer:
LiRa [457]3 years ago
6 0

Answer:

5.Rotation

6.Reflection

7.Reflection

8.Rotation

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HACTEHA [7]
Do you by any chance have a graphing calculator?
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3 years ago
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At Sundae King, 4 of the last 6 sundaes sold had nuts. Considering this data, how many of
nordsb [41]

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12

Step-by-step explanation:

4/6=2/3

18(2/3)=12

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The sum of three numbers is 88. The first number is 8 more than the second. The third number is 3 times the second. What are the
Sever21 [200]

Answer:

The numbers are 24, 16 and 48

Step-by-step explanation:

For this equation you need to use all the information you have to add in 3 variables, use the information you have to connect them, so you only use one number. You’ll have the second number (x), the first number (x+8) and the third number (3x) now we use all of that to make an equation.

88=x+(x+8)+3x

Now you simplify the equation,

88=5x+8

Now get the x and it’s coefficient alone on one side

80=5x

Now divide both sides so the x is alone

x=16

Since the second number was x you know the second number

the first number is x+8 since x is 16 the first number is 24

The third number is 3 * x so the third number is 48.

So the numbers are 24, 16 and 48

5 0
3 years ago
J.D. power and Associates calculates and publishes various statistics concerning car quality. The dependability score measures p
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Answer:

0.281 ; 0.864

Step-by-step explanation:

1.)

p decreases as n increases (n increases, p--> 0)

λ ≥ 0

P(x = x) = (e^-λ * λ^x) ÷ x!

λ for Ford = 1.27

B) zero problems :

P(x = 0) :

(e^-1.27 * 1.27^0) ÷ 0! = 0.281

P(x = 0) = 0.281

Two or fewer problems :

P(x ≤ 2) = p(x = 0) + p(x = 1) + p(x = 2)

P(x ≤ 2) = 0.281 + 0.357 + 0.226

P(x ≤ 2) = 0.864

D.) It allows for early detection and thus adequate curtailment of the problem at an a stage in which it seems easier to curb.

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3 years ago
-5x +7=-38 please help meee
Sedaia [141]

Answer:

-5x+7=-38

-5x=-45

x=9

Step-by-step explanation:

7 0
3 years ago
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