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Ulleksa [173]
3 years ago
10

Help with algebraic equation and to solve it plz

Mathematics
1 answer:
lutik1710 [3]3 years ago
7 0
4) fifteen less than y is 32

15 - y= 32

15 - (-17)= 32

two negatives become positive so 15+17= 32


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Let B1W2 denote the outcome that the first ball drawn is B1 and the second ball drawn is W2. Because the first ball is replaced
Sati [7]

Answer:

\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\

W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}

Step-by-step explanation:

\text{If an urn contains two blue balls} (denoted \:B_1 \:and \:B_2) \text{and three white balls},(denoted \:W_1, W_2, \:and\: W_3)

If One ball is drawn, its color is recorded, and it is replaced in the urn. Then another ball is drawn and  its color is recorded.

The 25 Possible outcomes of this experiment are listed below:

\{B_1B_1, B_1B_2, B_1W_1, B_1W_2, B_1W_3, \\B_2B_1, B_2B_2, B_2W_1, B_2W_2, B_2W_3, \\

W_1B_1,W_1B_2, W_1W_1, W_1W_2, W_1W_3, \\W_2B_1, W_2B_2, W_2W_1,W_2W_2, W_2W_3, \\W_3B_1, W_3B_2, W_3W_1, W_3W_2, W_3W_3\}

The tree diagram of this event is also attached.

6 0
3 years ago
On Monday Sophie ran 4 5/6 laps of a running track and on Tuesday she ran 5 3/4
MatroZZZ [7]

Answer:

10  7/12

hope this is right

Step-by-step explanation:

4  5/6 = 29/6 as an improper fraction

5  3/4 = 23/4 as an improper fraction

you times the two denominators together = 24

you times 29 by 4 = 116

you times 23 by 6 = 138

you add 116 and 138 = 254

you put this over 24 =  254/24

simplify this = 127/12

you make this a mixed number = 10 7/12

the answer is 10 7/12

3 0
3 years ago
Evaluate the expression when g = 6 and h = 7 <br> h + 9g
Norma-Jean [14]
Sub the numbers in
7 + 9(6)
=7 + 54
=61
4 0
2 years ago
Read 2 more answers
digit at tens place of two digit number is twice the digit at units place .if sum of this number and the no.formed by reversing
Dima020 [189]
Let the number be     xy ,

xy = 10x + y.   when reversed = yx = 10y + x

x = 2y          ........(a)

10x + y + 10y + x = 66.........(b)

10(2y) + y + 10y + 2y = 66

20y + y + 10y + 2y = 66

33y = 66

y = 66/33

y = 2

x = 2y = 2*2 = 4

Recall the original number is xy =     42.
8 0
2 years ago
Solve.
yarga [219]
- 3/5x + 15 > 720
- 3/5x > 705
X < -423
5 0
2 years ago
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