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Andreas93 [3]
3 years ago
7

PLZ HELP NEED ASAP WITH WORK

Mathematics
2 answers:
prohojiy [21]3 years ago
4 0

Answer:

x > 15 or x < -6

Step-by-step explanation:

melamori03 [73]3 years ago
4 0

Answer: I dont understand

Step-by-step explanation:

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I need help with this one math question please!
den301095 [7]

Answer:

see explanation

Step-by-step explanation:

Assuming the fractions are being multiplied

Factorise the denominators of both fractions

x² - 3x - 10 = (x - 5)(x + 2)

x² + x - 12 = (x + 4)(x - 3)

The product can now be expressed as

\frac{x-5}{(x-5)(x+2)} × \frac{x+2}{(x+4)(x-3)}

Cancel (x - 5) and (x + 2) on the numerators/ denominators, leaving

\frac{1}{(x+4)(x-3)} = \frac{1}{x^2+x-12}

3 0
2 years ago
Your answer<br> What is the value of the expression? -50 + 51? *
bija089 [108]

Answer:

The answer is 1

Step-by-step explanation:

-50+50=1

3 0
2 years ago
Read 2 more answers
Simplify
enot [183]

5d(7-3)= 20d

20d-16d= 4d

3x2d= 6d

4d+6d= 10d

the answer you are looking for is 10d

7 0
3 years ago
A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

8 0
2 years ago
A newspaper prints that the average square footage of a house in Cleveland is significantly less than 2,379 square feet.
tatyana61 [14]

Answer: i’m confused on what the question is

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
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