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3 years ago

PLEASE HELP ME ASAP!! Answers: undefined Negative Zero Positive

Mathematics

2 answers:

Sveta_85 [38]3 years ago

8 0

I think positive since is rising ....

<h3>Please mark me as brainliest ......</h3>

Firdavs [7]3 years ago

3 0

Positive since it’s rising :)

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On Monday, during a one day sale, the price of a suit was decreased by 20%. On Tuesday, the price of the suit was changed back t

nignag [31]

Answer:

25%

Step-by-step explanation:

If we consider the original price of the piece of suit is x.

Given that, on Monday during a one day sale, the price of the suit was decreased by 20%.

Therefore, the new price of the suit on Monday is $x( 1 - \frac{20}{100}) = 0.8x$ .

Now, the price of the suit on Tuesday was changed back to the original price i.e. x.

Therefore, the price is increase by (x - 0.8x) = 0.2x from the price of 0.8x.

So, the percentage change in price of the suit on Tuesday is $\frac{0.2x}{0.8x} \times 100 = 25$ %. (Answer)

8 0

3 years ago

A starting lineup in basketball consists of two guards, two forwards, and a center. (a) a certain college team has on its roster

julsineya [31]

1 . Consider lineups without x. You have to select

2 guards from 5 quards;
2 forwards from 3 forwards;
1 center from 4 centers.

It can be made in

$C_5^2\cdot C_3^2\cdot C_4^1=10\cdot 3\cdot 4=120$ different ways.

2. Consider lineups with x as guard. You have to select

2 guards from 6 quards (one of them must be x);
2 forwards from 3 forwards;
1 center from 4 centers.

It can be made in

$C_5^1\cdot C_3^2\cdot C_4^1=5\cdot 3\cdot 4=60$ different ways.

3. Consider lineups with x as forward. You have to select

2 guards from 5 quards;
2 forwards from 4 forwards (one of them must be x);
1 center from 4 centers.

It can be made in

$C_5^2\cdot C_3^1\cdot C_4^1=10\cdot 3\cdot 4=120$ different ways.

Therefore, the total number of different lineups is

120+60+120=300.

5 0

3 years ago

Read 2 more answers

Assume that there are an equal number of births in each month so that the probability is that a person chosen at random was born

NikAS [45]

Answer:

0.2773 = 27.73% probability that at the May celebration, exactly two members of the group have May birthdays

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they have a birthday in May, or they do not. The probability of a person having a birthday in May is independent of any other person. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$