2x + 50 = 7x
50 = 5x
10 = x
2 (10) + 50
20 + 50
70
m<AEB = 70 degrees
<u>Answer:</u>
7 inches
<u>Step-by-step explanation:</u>
The dimension of the rectangular gift is 10 by 12 inches so let us find the perimeter of this rectangle.
Perimeter of rectangular gift = 2 (L+ W) = 2 (10 +12) = 44 inches
Since we are to use the same length of ribbon to wrap a circular clock so the perimeter or circumference of the clock should be no more than 44 inches.
Therefore, the maximum radius of the circular clock is 7 inches.
The fundamental theorem of calculus tells us that
So we have
and