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Oksi-84 [34.3K]
3 years ago
9

Please Help me with a 8th-grade math question please

Mathematics
1 answer:
Valentin [98]3 years ago
6 0

Answer:

$88

Step-by-step explanation:

55 percent of 160 is 88

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The graph shows the functions f(x), p(x), and g(x):
Sidana [21]
The function f(x) is:

f(x)=x

This is because the line f(x) passes through the points (-1,-1), (0,0), (1,1) etc.

The function p(x) is:

p(x)=mx+C

Whereby (m) is the slope and (C) is a constant.

m=-4/3, as m=tan(ω)=O/A=-4/3 as slope is negative.

Now when y=-3, x=-3.

So:

-3=-4/3 *(-3) +C

-3= 4 + C

C=-7

This means that:

p(x)=-4/3x -7

Now, where p(x)=g(x), x=-6.

p(-6)=-4/3 * (-6) -7

p(-6)=24/3 -7

p(-6)=8-7

p(-6)=1

Therefore:

p(x) and g(x) meet at (-6, 1) and the solution to p(x)=g(x) is x=-6.
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3 years ago
Tracy found the length of GF. Her work is shown below.
Svetlanka [38]

Answer:

She used GF = 2BG, but the correct statement is BG = 2GF.

Step-by-step explanation:

7 0
3 years ago
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HELP PLZ
Sedbober [7]
The answer is a.............
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3 years ago
Given the sequence in the table below, determine the sigma notation of the sum for term 4 through term 15
goblinko [34]
a_n=5 \ for \ n=1 \\
a_n=-10 \ for \ n=2 \\
a_n=20 \ for \ n=3

You can see it's a geometric sequence because the ratio is constant (\frac{a_3}{a_2}=\frac{a_2}{a_1}).
The nth term of a geometric sequence:
a_n=a_1 \times r^{n-1}

a_1=5 \\
r=\frac{a_2}{a_1}=\frac{-10}{5}=-2 \\ \\
a_n=5(-2)^{n-1}

It has to be the sum for term 4 through term 15, so n=4 and the number above the sigma is 15.

Your answer:
\sum^{15}_{n=4} 5(-2)^{n-1}
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What are the solutions of 4x2 - 8x +5 = 0 ?
MrRissso [65]

Answer:

x= {2+ i}/2 , {2- i}/2 = C

Step-by-step explanation:

4x² - 8x +5 = 0

using quadratic formula

x= {-b±√b²-4ac}/2a

x= [-(-8)±√(-8)²-4(4)(5)] /2x4 = [8±√64-80]/8= [8±√-16]/8 = {8±4 i}/8

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4 divides 8

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3 years ago
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