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stich3 [128]
3 years ago
13

Use completing the square to solve the equation x^2 0 10x = 08.

Mathematics
1 answer:
wariber [46]3 years ago
4 0
Ok so assuming the 0 means minus from typing problems

x^2-10x=-8

to completet  the square
make sure the term in front of x^2 is 1
that is correct
then take 1/2 of the term in front of the x term and square it
-10/2=-5, (-5)^2=25
add that to both sides
x^2-10x+25=17


answer is the first equation
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What is -3(-6+8)^3-2(1-3)^3
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Assignment: \bold{Solve \ Equation: \ -3\left(-6+8\right)^3-2\left(1-3\right)^3}

<><><><><>

Answer: \boxed{\bold{-8}}

<><><><><>

Explanation: \downarrow\downarrow\downarrow

<><><><><>

[ Step One ] Follow PEMDAS Order Of Operations; Calculate Within Parenthesis

Note: \bold{PEMDAS: \ Parenthesis, \ Exponents, \ Multiply, \ Divide, \ Add, \ Subtract}

\bold{-6+8: \ 2}

[ Step Two ] Rewrite Equation

\bold{-3\cdot \:2^3-2\left(1-3\right)^3}

[ Step Three ] Calculate Within Parenthesis

\bold{1-3: \ -2}

[ Step Four ] Rewrite Equation

\bold{-3\cdot \:2^3-2\left(-2\right)^3}

[ Step Five ] Calculate Exponents

\bold{2^3: \ 8}

[ Step Six ] Rewrite Equation

\bold{-3\cdot \:8-2\left(-8\right)}

[ Step Seven ] Multiply

\bold{2\left(-8\right): \ -16}

[ Step Eight ] Rewrite Equation

\bold{-24-\left(-16\right)}

[ Step Nine ] Subtract

\bold{-24-\left(-16\right): \ -8}

[ Step Ten ] Rewrite Equation

\bold{-8}

<><><><><><><>

\bold{\rightarrow Mordancy \leftarrow}

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