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Monica [59]
3 years ago
11

How did they get 72?

Mathematics
2 answers:
Anon25 [30]3 years ago
8 0

Answer: 12x6=72 get it?

Step-by-step explanation:

lyudmila [28]3 years ago
6 0

Answer:

they multiplied all the sides

Step-by-step explanation:

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What is the exact length of AB
Tatiana [17]

We have the formula S= r * theta , where S is arc length , r is radius , and theta is central angle in radians

So AB= 4 * 45* π/180 = π units

6 0
3 years ago
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#3 pls????????????????
zvonat [6]

Answer:

ΔGFE≈ΔJKL

Step-by-step explanation:

5 0
3 years ago
Find the polar equation of the conic with the focus at the pole, directrix x = 4, and eccentricity 1.
BabaBlast [244]

Answer:

Choice D is correct

Step-by-step explanation:

The eccentricity of the conic section is 1, implying we are looking at a parabola. Parabolas are the only conic sections with an eccentricity of 1.

Next, the directrix of this parabola is located at x = 4. This implies that the parabola opens towards the left and thus the denominator of its polar equation contains a positive cosine function.

Finally, the value of k in the numerator is simply the product of the eccentricity and the absolute value of the directrix;

k = 1*4 = 4

This polar equation is given by alternative D

6 0
3 years ago
Given: circle k(O), m AM=125°, m EF=31°, m∠MAF=75°. Find: m∠AME
Bess [88]

Answer:

58°

Step-by-step explanation:

If m AM=125°, then m∠AOM=125°.

If m∠MAF=75°, then m∠MOF=150° (because central angle MOF subtends on the same arc as inscribed angle MAF).

Thus,

m∠FOA=360°-150°-125°=85°.

If mEF=31°, then m∠EOF=31° (as central angle subtended on the arc EF).

Hence,

m∠EOA=m∠EOF+m∠FOA=31°+85°=116°.

Angle EOA is central angle subtended on arc EA, angle AME is inscribed angle subtended on arc AE, thus

m∠AME=1/2m∠EOA=58°.

7 0
3 years ago
Let U = {3, 6, 9, 12, 15, 18, 21, 24} and A = {9, 12, 15, 21}. A'
miskamm [114]

Answer:

A¹ = { 3 , 6, 18 , 24}

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u>Universal set </u>

If all the sets under consideration are the subsets of a fixed set 'U' then the set 'U' is called the Universal set.

Given  U = {3, 6, 9, 12, 15, 18, 21, 24}

Given A = {9, 12, 15, 21}

<u><em>Compliment Of A</em></u>

The Complement of a set A is all the objects that do not belong to set A

The Compliment of A is denoted by A¹

A¹ = U - A

     = {3, 6, 9, 12, 15, 18, 21, 24} - {9, 12, 15, 21}

A¹ = { 3 , 6, 18 , 24}

4 0
3 years ago
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