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Black_prince [1.1K]
4 years ago
10

What is the relationship between a and b? last answer is none of the above!

Mathematics
2 answers:
Zolol [24]4 years ago
8 0

Answer:

B) Complementary angles

Step-by-step explanation:

∠AXB + ∠CXB = 180    { Straight line}

∠AXB + 90 = 180          { given  ∠CXB=90}

∠AXB = 180 - 90

∠AXB = 90

a + b = 90

If sum of two angles is 90, then the two angles are complementary angles.

LUCKY_DIMON [66]4 years ago
7 0

Answer:

its B I think. because it should equal 90°

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sergey [27]

Answer:

Step-by-step explanation:

\displaystyle \Large \boldsymbol{} 5\cdot  \sqrt{3:2\sqrt{3-\sqrt{2} } }  =\\\\\\ 5\cdot  \sqrt{\frac{3}{2\sqrt{3-\sqrt{2} } } \cdot \frac{2\sqrt{3+\sqrt{2} } }{2\sqrt{3+\sqrt{2} } } } = \\\\\\5\cdot  \sqrt{\frac{6\sqrt{3+\sqrt{2} } }{4\cdot \sqrt{9-2} } }  =5\sqrt{\frac{6\sqrt{3+\sqrt{2} } }{2\sqrt{7} } }

But if the condition would be like this

\displaystyle \Large \boldsymbol{} 5\cdot  \sqrt{3:2\sqrt{3-\boldsymbol2\sqrt{2} } }  =\\\\\\5\cdot \sqrt{\frac{3}{2\cdot \sqrt{\underbrace{2+1-2\sqrt{2} \cdot \sqrt{1} }_{(\sqrt{2} -1)^2} } }} =\\\\\\5\cdot \sqrt{\frac{3}{2\cdot (\sqrt{2}-1) } } } = \\\\\\ 5\cdot  \sqrt{\frac{3}{2(\sqrt{2}-1 )}  \cdot \frac{\sqrt{2} +1}{\sqrt{2}+1 }}   =5 \sqrt{\frac{3}{2(2-1)} }  =\boxed{5\sqrt{1,5} }

8 0
3 years ago
A researcher surveyed 80 adults and found that 22 regularly run for exercise and 18 regularly swim for exercise.
Aliun [14]
Whenever the questions asks for the probability and has "or" you have to add the two probabilities. In the same way, "and" implies multiplication. Therefore, the probability that someone swims is:
\frac{18}{80} =  \frac{9}{40}

Probability that someone runs:
\frac{22}{80} =  \frac{11}{40}

Thus, if you add them:
\frac{9}{40} +  \frac{11}{40} =  \frac{20}{40}  =  \frac{1}{2}

So, the probability that someone swims <em>or</em> runs is 1/2 or 50%.
6 0
3 years ago
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My guess is the bottom right.
5 0
3 years ago
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5 0
3 years ago
Write the equation of an ellipse with vertices at (7, 0) and (-7, 0) and co-vertices at (0, 1) and (0, -1).
Irina-Kira [14]

Answer:

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Step-by-step explanation:

In this problem we have a horizontal ellipse, because the major axis is the x-axis

The equation of a horizontal ellipse is equal to

\frac{(x-h)^{2}}{a^{2}}+\frac{(y-k)^{2}}{b^{2}} =1

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(h,k) is the center of the ellipse

a and b  are the respective vertices distances from center

we have

vertices at (7, 0) and (-7, 0)

co-vertices at (0, 1) and (0, -1)

so

The center is the origin (0.0) (The center is the midpoint of the vertices)

a=7

b=1

substitute

\frac{(x-0)^{2}}{7^{2}}+\frac{(y-0)^{2}}{1^{2}}=1

\frac{(x)^{2}}{49}+\frac{(y)^{2}}{1}=1

8 0
3 years ago
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