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Nonamiya [84]
2 years ago
6

Determine if f (x) = -x^3 + 4x^2 +7x - 6 is a odd or even degree

Mathematics
2 answers:
geniusboy [140]2 years ago
7 0

Answer:

Neither

Step-by-step explanation:

It has a y intercept, which is -6, which changes the whole graph, so its neither

Stella [2.4K]2 years ago
6 0

Answer:

odd

Step-by-step explanation:

the leading term of the polynomial (the term in a polynomial which contains the highest power of the variable) is -x^3

the degree is 3, which is odd

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gladu [14]

Answer:

24 fluid ounces

Step-by-step explanation:

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2 years ago
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Let v1=(1, 6) and v2=(5, -3)
astraxan [27]

Answer:

See Explanation;

Step-by-step explanation:

The given vectors are;

v_1=\:\: and v_2=\:\:

a) To add or subtract two vectors, we add or subtract their corresponding components

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v_1+v_2=\:\:

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v_1-v_2=\:\:

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b) See attachment for graphs(1,6

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2 years ago
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
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2 years ago
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inna [77]

Answer: 70

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I hope this is good enough:

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Ronch [10]

Answer:

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