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2 years ago

On the unit circle, which of the following angles has the terminal point coordinates of (\sqrt(2))/(2),-(\sqrt(2))/(2)

Mathematics

1 answer:

kondor19780726 [428]2 years ago

3 0

Answer:

c)3pi/4

Step-by-step explanation:

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Simplify the expression below. 3c - 2cd - 8c + 7d

jolli1 [7]

<span>3c - 2cd - 8c + 7d
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3 years ago

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2 years ago

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Aneli [31]

Hope this helps explain what was needed to be solved! :)

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2 years ago

Write an expression with a value of 12.it should contain four numbers and two different operations

sergey [27]

Roughly what I gave your doppelganger (you + 1) a few minutes ago . . .

[ (4 + 3)² - 1 ] divided by (7 - 3) .

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3 years ago

The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control a

Dafna11 [192]

Answer:

Probability that at least 490 do not result in birth defects = 0.1076

Step-by-step explanation:

Given - The proportion of U.S. births that result in a birth defect is approximately 1/33 according to the Centers for Disease Control and Prevention (CDC). A local hospital randomly selects five births and lets the random variable X count the number not resulting in a defect. Assume the births are independent.

To find - If 500 births were observed rather than only 5, what is the approximate probability that at least 490 do not result in birth defects

Proof -

Given that,

P(birth that result in a birth defect) = 1/33

P(birth that not result in a birth defect) = 1 - 1/33 = 32/33

Now,

Given that, n = 500

X = Number of birth that does not result in birth defects

Now,

P(X ≥ 490) = $\sum\limits^{500}_{x=490} {^{500} C_{x} } (\frac{32}{33} )^{x} (\frac{1}{33} )^{500-x}$

= ${^{500} C_{490} } (\frac{32}{33} )^{490} (\frac{1}{33} )^{500-490}$ + .......+ ${^{500} C_{500} } (\frac{32}{33} )^{500} (\frac{1}{33} )^{500-500}$

= 0.04541 + ......+0.0000002079

= 0.1076

⇒Probability that at least 490 do not result in birth defects = 0.1076

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2 years ago