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emmasim [6.3K]
3 years ago
5

Company A has a project plan for a new product under development. The product will be one of many released in the coming year. T

he plan, if disclosed, might give Company A's competition a market advantage. Which ISO 27002 classification level is most likely assigned to this document?
a) Public Documents
b) Proprietary
c) Highly Confidential
d) Top Secret
Computers and Technology
1 answer:
gizmo_the_mogwai [7]3 years ago
4 0

Answer:

Company A

The ISO 27002 classification level that is most likely assigned to this document is:

b) Proprietary

Explanation:

The ISO 27002 classification levels adopted by commercial organizations are Restricted (top secret is preferred in government circles), Confidential, Internal (or proprietary), and Public. Since the new product is under development, one of many, and most likely known to the project team, the project plan will be classified as Proprietary.  Company A designates this document as Proprietary or Internal to show that disclosure of the information to its competitors is not allowed.  This level of classification shows that Company A can establish intellectual property rights over the document.

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4.2: Roman Numeral Converter Write a program that asks the user to enter a number within the range of 1 through 10. Use a switch
Reptile [31]

Answer:

The solution code is written in Java

  1. import java.util.Scanner;
  2. public class Main {
  3.    public static void main (String [] args) {
  4.        Scanner inStream = new Scanner(System.in);
  5.        System.out.print("Please input a number (1 - 10): ");
  6.        int num = inStream.nextInt();
  7.        if(num < 1 || num > 10){
  8.            System.out.println("The input must be between 1 - 10");
  9.        }else{
  10.            switch(num){
  11.                case 1:
  12.                    System.out.println("I");
  13.                    break;
  14.                case 2:
  15.                    System.out.println("II");
  16.                    break;
  17.                case 3:
  18.                    System.out.println("III");
  19.                    break;
  20.                case 4:
  21.                    System.out.println("IV");
  22.                    break;
  23.                case 5:
  24.                    System.out.println("V");
  25.                    break;
  26.                case 6:
  27.                    System.out.println("VI");
  28.                    break;
  29.                case 7:
  30.                    System.out.println("VII");
  31.                    break;
  32.                case 8:
  33.                    System.out.println("VIII");
  34.                    break;
  35.                case 9:
  36.                    System.out.println("IX");
  37.                    break;
  38.                case 10:
  39.                    System.out.println("X");
  40.                    break;
  41.            }
  42.        }
  43.    }
  44. }

Explanation:

The first part of this program (Line 6 - 8) is to get input number from user using Scanner object. Input validation has been done to check if the input number is in the acceptable range (Line 10). If not, an error message will be displayed (Line 11).

If the input number is in the range of 1 - 10, the number will go through a series of switch statements checking. If the number meet the condition in one of the switch cases, it will print the corresponding roman numeral specified in the case block (Line 13 - 44). For example, if input number is 9, the case 9 condition is met and "IX" will be printed.

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Explanation:

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