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KatRina [158]
3 years ago
15

Help Plz

Mathematics
1 answer:
hichkok12 [17]3 years ago
7 0

Answer:

Yes , it is independent

Step-by-step explanation:

independent

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What is 88.2 rounded to the nearest whole number?​
HACTEHA [7]

Answer:

88

Step-by-step explanation:

if the decimal is below 5 then round down

8 0
3 years ago
Read 2 more answers
Using algebra tiles, form a rectangle to represent each of the following
RideAnS [48]

Answer:

Answer is below

Step-by-step explanation:

I graphed all of the expressions on the graph below to find the solutions of the expressions.

If these answers are correct, please make me Brainliest!

3 0
3 years ago
Please help me solve this
Tpy6a [65]

Answer:

<u>1st pic:</u>

x = 49

top angle = 45

bottom angle = 108

far right angle = 27 degrees

<u>2nd pic:</u>

angle 1 = 88 degrees

angle 2 = 57 degrees

angle 3 = 35 degrees

angle 4 = 145 degrees

Step-by-step explanation:

<u>1st pic:</u>

you can find the far right angle by taking 153 and subtracting it from 180:

⇒ 180 - 153 = 27 degrees

you can find x by the following equation ⇒ x - 4 + 2x + 10 + 27 = 180

combine like terms ⇒ 3x + 33 = 180

subtract 33 from each side ⇒ 3x + 33 - 33 = 180 - 33 ⇒ 3x = 147

divide 3 on each side: ⇒ \frac{3x}{3} = \frac{147}{3}

x = 49

to find the top and bottom angles, substitute 49 for x:

top angle : x - 4

49 - 4 = 45 degrees

bottom angle: 2x + 10

2 x 49 + 10 = 108 degrees

<u>2nd pic:</u>

angle 1:

⇒ 180 - 92 = 88 degrees

angle 2:

⇒ 180 - 123 = 57 degrees

angle 3:

⇒ 180 - (88 + 57) = 35 degrees

angle 4:

⇒ 180 - 35 = 145 dgerees

4 0
3 years ago
Use your pointless mathematic skills to solve 9+10=21
alekssr [168]
The answer is 9+ 10=22
6 0
3 years ago
Pre-Cal - Someone please help! (Image Attached)
olasank [31]
Note that \displaystyle{ \sin30^{\circ}= \frac{1}{2} and \displaystyle{ \cos30^{\circ}= \frac{ \sqrt{3}}{2}.

From the unit circle, we can check that \sin30^{\circ} and \sin(-30)^{\circ} have the same value, but opposite signs, that is:

\sin(-30)^{\circ}=-\sin(30)^{\circ}=-\frac{1}{2}. 


Thus, 
\displaystyle{ \cos(x-y)= \cos(-30^{\circ}-60^{\circ})=cos(-90^{\circ}).


Note that cos(-90^{\circ}) is the x-coordinate of the lowest point on the unit circle, that is (0, -1). Thus cos(-90^{\circ})=0


Answer: 0

6 0
3 years ago
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