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yKpoI14uk [10]
3 years ago
10

Plz help me with this

Mathematics
1 answer:
stich3 [128]3 years ago
4 0

Answer:  \bold{log\ x=\dfrac{log\ P}{y}}

<u>Step-by-step explanation:</u>

To eliminate the exponent, apply log to both sides.  This allows the exponent to become the coefficient, which can then be divided from both sides.

x^y=P\\\\log\ x^y=log P\\y\cdot log\ x=log\ P\\\large\boxed{log\ x=\dfrac{log\ P}{y}}

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A triangle has lengths of 3 cm, 5 cm, and 9 cm, can it form 1 or more triangles?
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Step-by-step explanation:

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3 years ago
Consider the function.
Mariana [72]

Answer: (2 1/2, 0) (the last option)

Step-by-step explanation:

I guess the function is:

f(x) = (2  1/2) - (3  1/2)*x

now, the rule for f-1(x) that we know is:

f-1( f(x) ) = x.

So if we want to find the x-intercept of f-1(x), we must evaluate it in f(0)

f-1(f(0)) = 0.

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3 years ago
What is the area of the trapezoid?
Rainbow [258]

Answer:

256m²

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4 0
3 years ago
Read 2 more answers
A building society offers a rate of 11% per annum simple interest. Beth-Ann deposit 24000 in the society for 15 months. Calculat
Nostrana [21]

Answer:

The amount of money due to Beth-Ann at the end of this period​ is $27, 300.

Step-by-step explanation:

The amount at the end of a period, when simple interest is being charged is:

Amount (A) = Principal (P) + Interest (I)

Here interest is computed using the formula:

I=P\times R\times T

It is provided that:

P = 24,000

R = 11%

T = 15 months = 1.25 years

Compute the Interest as follows:

I=P\times R\times T

  =24000\times 0.11\times 1.25\\=3300

The interest earned is, <em>I</em> = $3,300.

Compute the amount of money due to Beth-Ann at the end of this period​ as follows:

A=P+I

   =24000+3300\\=27300

Thus, the amount of money due to Beth-Ann at the end of this period​ is $27, 300.

7 0
3 years ago
Please please please please helppppp
Marizza181 [45]
For question 3. A
4. A
5. B
6 0
3 years ago
Read 2 more answers
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