Answer: 11378.58 ft
Step-by-step explanation:
1. Draw a figure like the one attached, where A is the position of the airplane and B and C are the positions of the cars.
2. The distance between the cars is the length BC, then, you need to calculate the measure of BD and DC to add them and obtain BC.
<h2> 3. You know the opposite side and the angles of depression, then, you can calculate the distance between the cars as following:</h2>
Answer:
B. 6:00
Step-by-step explanation:
There are 60 minutes in one hour.
To calculate 40 minutes after 4:40, separate 40 minutes into two lots of 20 minutes.
⇒ 4:40 + 20 minutes = 5:00
⇒ 5:00 + 20 minutes = 5:20
Therefore, 40 minutes after 4:40 is 5:20
To calculate the time that 5:20 is 40 minutes before, add 40 minutes to 5:20
⇒ 5:20 + 40 minutes = 6:00
Therefore, the solution is option B. 6:00
x = -9
-3x when x is 3 would be -3(3) = -9
The trial and error method is used to find an initial factor:
If we let f(x) = x³ - x² - 24x - 36 and all we have to do is sub' in values of x until
f(x) = 0, we can use this to find an initial factor by the factor theorem:
f(1) = (1)³ - (1)² - 24(1) - 36 = -60
f(2) = (2)³ - (2)² - 24(2) - 36 = -80
f(5) = (5)³ - (5)² - 24(5) - 36 = -56
*** f(6) = (6)³ - (6)² - 24(6) - 36 = 0 ***
f(6) = 0 so (x - 6) is a factor of f(x).
This means that: f(x) = x³ - x² - 24x - 36 = (x - 6)(ax² + bx + c).
To find a,b and c, use long division (or inspection) to divide x³ - x² - 24x - 36 by x - 6.
The other 2 factors of f(x) can then be found by factorizing the
ax² + bx + c quadratic the way you would with any other quadratic (i.e. by quadratic formula, CTS or inspection).
